uri
  • uri
Halp meh pliss, The number of positive values of x less than 360 degrees which satisfy the equation sin 1/2x =cos x is? a)0 b)1) c)2 d)3 e)4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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saifoo.khan
  • saifoo.khan
You do math too? D:
hba
  • hba
Mujhe bhi yaqeen nahi horaha :P
anonymous
  • anonymous
looks like there are two http://www.wolframalpha.com/input/?i=sin%28x%2F2%29%2Ccos%28x%29+domain+0..2pi

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More answers

yrelhan4
  • yrelhan4
write cosx in terms of sin^2 x/2 and solve!
uri
  • uri
1/2x=sin^2x/2 Right ?
yrelhan4
  • yrelhan4
cosx= 1-2sin^2 (x/2)
yrelhan4
  • yrelhan4
you get a quadratic.. solve for x..
uri
  • uri
2sin^2(x/2)+cosx-1=0
yrelhan4
  • yrelhan4
2t^2 + t -1=0 where t=sin(x/2)
uri
  • uri
Quad,breaking the middle term or completing the square method?
yrelhan4
  • yrelhan4
breaking the middle term.. you would get (2t-1)(t+1)=0 where t=sin(x/2)
uri
  • uri
eh,2t-1=0=)t=1/2 t+1=0=)t=-1
yrelhan4
  • yrelhan4
yup!
uri
  • uri
Sin(x/2)=1/2 Sin(x/2)=-1
yrelhan4
  • yrelhan4
so there would be 3 values of x/2 in 0 to 360.. 30,120,270. so x=60,240,540.. since you want from 0 to 360.. there would be 2 solns..
uri
  • uri
it was Sin x/2
yrelhan4
  • yrelhan4
if sin(x/2) = 1/2 , what is x? 0>x>360
hba
  • hba
Oh so, sin x/2 =cos x ?
yrelhan4
  • yrelhan4
1- sin^2(x/2)= cosx @hba
uri
  • uri
em BOREEEEEED.
yrelhan4
  • yrelhan4
look.. let x/2=k .. sin(k)=1/2 --> k=30, 120.. --> x=60, 240
yrelhan4
  • yrelhan4
cosx= 1-2sin^2 (x/2) @hba missed the two..
yrelhan4
  • yrelhan4
thik hai? @uri
sirm3d
  • sirm3d
@yrelhan4 since \(\displaystyle 0 \leq x \leq 360\) then \(\displaystyle 0 \leq \frac{x}{2} \leq 180\)
sirm3d
  • sirm3d
now, \(\sin x/2 = 1/2\) therefore \(x/2=30, 150\) or \(x=60, 300\)
uri
  • uri
Yrelhan GUESSSS WHAT?! I donyt undastand aaaanythang nd ima sho confuzzeld tooh,I caant eveen speel corractly. o.O
yrelhan4
  • yrelhan4
lol.. i am such a fool.. you are right! @sirm3d
uri
  • uri
Wut iz the aaansweeer?! none of my option matches your answer!
yrelhan4
  • yrelhan4
i just wrotw150 value wrong, right? why am i a fool then? :P
sirm3d
  • sirm3d
the other equation, \(\sin x/2 = -1\) has no solution in \(0 \leq \frac{x}{2} \leq 180\)
yrelhan4
  • yrelhan4
@uri 2.. final!
uri
  • uri
@sirm3d sinx/2=1 has no solution so we will leave it? xD
yrelhan4
  • yrelhan4
@uri its sin(x/2) = -1
uri
  • uri
k.
sirm3d
  • sirm3d
@uri, just count the number of solutions: \(x=60^0,\;300^0\)
uri
  • uri
@sirm3d 2 solutions?
sirm3d
  • sirm3d
yup. (C) 2
yrelhan4
  • yrelhan4
are kitni baar puchegi? @uri :P
uri
  • uri
AMG THANKYOUUUUUUUUUUUUU!AMG THANKYOUU SOO MUCHHHHH!!!! :D
yrelhan4
  • yrelhan4
mera medal.. :'( .. aadha to maine solve kiya..
yrelhan4
  • yrelhan4
huh!
uri
  • uri
You have 2 now :P
yrelhan4
  • yrelhan4
haha.. he's got 2 now too!
uri
  • uri
Happy? :D
yrelhan4
  • yrelhan4
ha! yes.. :P
uri
  • uri
Yw xD

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