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help123456

  • 3 years ago

a^2 – a – 20 can you help me solve this idk why I keep getting messed up on this

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  1. mathstudent55
    • 3 years ago
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    Set up two sets of parentheses: ( )( ) Place a on the left of each parentheses: (a )(a ) Your middle term is -a which means -1a, and your last term is -20 Now look for two numbers that multiply to -20 and add to -1 What are they? That's what goes inside the parenteses on the right sides.

  2. help123456
    • 3 years ago
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    -5, and -4

  3. Loujoelou
    • 3 years ago
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    K so we have to factor a^2-a-20. We need to find two factors that when multiplied will equal -1 and when added equal -20. If we go through the factors of -20, we find that the two numbers that do this are -5 & 4. -5*4=-20 & -5+4=-1 so it fits what we're looking for. Now we put this in the two sets of parenthesis we have- (a )(a ) and it becomes (a+4)(a-5)

  4. help123456
    • 3 years ago
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    wait y is one negative and one positive

  5. Loujoelou
    • 3 years ago
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    Because we are looking for 2 numbers that multiply to get -20. A positive*positive=positive negative*negative=positive positive*negative=negative. So that means one of the numbers will be negative & the other positive. Also these 2 numbers have to add up to -1. The only two numbers that will meet this are -5 & 4. -5*4=-20 and -5+4=-1.

  6. mathstudent55
    • 3 years ago
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    It's -5 and 4 because -5 x 4 = -20 and -5 + 4 = -1 So now those numbers go in the parentheses. (a - 5)(a + 4) And you're done.

  7. help123456
    • 3 years ago
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    o ok thank you

  8. Loujoelou
    • 3 years ago
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    no prob. :)

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