help please(: 1 over 3 (2x − 8) = 4

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help please(: 1 over 3 (2x − 8) = 4

Mathematics
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\[\frac{1}{3(2x-8)}=4\] What do you suggest from here?
  • hba
\[\frac{ 1 }{ 3(2x-8) }=4\] Use distributive property to evaluate your denominator
@Limitless its 1 over 3 and next to (2x − 8) = 4

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\[\frac{1}{3}(2x-8)=4\] What do you suggest from here?
@Limitless distributing?
  • hba
\[\frac{ 1 }{ 3 }(2x-8)=4\] 1)Multiply both sides by 3
@sylinan Sure. Then what?
@hba doesnt it cancel out?
  • hba
Yes.
You get \[\frac{2}{3}x-\frac{8}{3}=4.\]
  • hba
@Limitless Stop complicating it.
im getting confused ):
  • hba
Multiply your question by 3
@hba Complicating it would be using the Taylor series for \(x\). I apologize for replying when she was talking to you; I misread the post.
  • hba
@sylinan \[\frac{ 1 }{ 3 }(2x-8)=4\] Multiply both sides by 3.
  • hba
\[3 \times\frac { 1 }{ 3 }(2x-8)=4 \times 3\]
  • hba
@sylinan I know you can do it now :)
@hba okay so far i got 3(2x-8)=12
  • hba
Now see this \[\ \cancel 3 \times \frac{ 1 }{\ \cancel 3 }(2x-8)=4 \times 3\]
so then its 1(2x-8)=12?
  • hba
Now add both sides by 8
i thought i was suposed to do distribute the one?
  • hba
It doesn't make a diff It will stay the same :)
true okay so i got x=10?
  • hba
Yeaahhhh :D
  • hba
You are right :P
thank you (: help me with one more?(:
  • hba
Sure,Please post your question in a new tab :)
okay so open a new question?
  • hba
Yeah. The CoC says that not me :P
oh okay (:

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