anonymous
  • anonymous
help please(: 1 over 3 (2x − 8) = 4
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\frac{1}{3(2x-8)}=4\] What do you suggest from here?
hba
  • hba
\[\frac{ 1 }{ 3(2x-8) }=4\] Use distributive property to evaluate your denominator
anonymous
  • anonymous
@Limitless its 1 over 3 and next to (2x − 8) = 4

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anonymous
  • anonymous
\[\frac{1}{3}(2x-8)=4\] What do you suggest from here?
anonymous
  • anonymous
@Limitless distributing?
hba
  • hba
\[\frac{ 1 }{ 3 }(2x-8)=4\] 1)Multiply both sides by 3
anonymous
  • anonymous
@sylinan Sure. Then what?
anonymous
  • anonymous
@hba doesnt it cancel out?
hba
  • hba
Yes.
anonymous
  • anonymous
You get \[\frac{2}{3}x-\frac{8}{3}=4.\]
hba
  • hba
@Limitless Stop complicating it.
anonymous
  • anonymous
im getting confused ):
hba
  • hba
Multiply your question by 3
anonymous
  • anonymous
@hba Complicating it would be using the Taylor series for \(x\). I apologize for replying when she was talking to you; I misread the post.
hba
  • hba
@sylinan \[\frac{ 1 }{ 3 }(2x-8)=4\] Multiply both sides by 3.
hba
  • hba
\[3 \times\frac { 1 }{ 3 }(2x-8)=4 \times 3\]
hba
  • hba
@sylinan I know you can do it now :)
anonymous
  • anonymous
@hba okay so far i got 3(2x-8)=12
hba
  • hba
Now see this \[\ \cancel 3 \times \frac{ 1 }{\ \cancel 3 }(2x-8)=4 \times 3\]
anonymous
  • anonymous
so then its 1(2x-8)=12?
hba
  • hba
Now add both sides by 8
anonymous
  • anonymous
i thought i was suposed to do distribute the one?
hba
  • hba
It doesn't make a diff It will stay the same :)
anonymous
  • anonymous
true okay so i got x=10?
hba
  • hba
Yeaahhhh :D
hba
  • hba
You are right :P
anonymous
  • anonymous
thank you (: help me with one more?(:
hba
  • hba
Sure,Please post your question in a new tab :)
anonymous
  • anonymous
okay so open a new question?
hba
  • hba
Yeah. The CoC says that not me :P
anonymous
  • anonymous
oh okay (:

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