## sylinan Group Title help please(: 1 over 3 (2x − 8) = 4 one year ago one year ago

1. Limitless

$\frac{1}{3(2x-8)}=4$ What do you suggest from here?

2. hba

$\frac{ 1 }{ 3(2x-8) }=4$ Use distributive property to evaluate your denominator

3. sylinan

@Limitless its 1 over 3 and next to (2x − 8) = 4

4. Limitless

$\frac{1}{3}(2x-8)=4$ What do you suggest from here?

5. sylinan

@Limitless distributing?

6. hba

$\frac{ 1 }{ 3 }(2x-8)=4$ 1)Multiply both sides by 3

7. Limitless

@sylinan Sure. Then what?

8. sylinan

@hba doesnt it cancel out?

9. hba

Yes.

10. Limitless

You get $\frac{2}{3}x-\frac{8}{3}=4.$

11. hba

@Limitless Stop complicating it.

12. sylinan

im getting confused ):

13. hba

14. Limitless

@hba Complicating it would be using the Taylor series for $$x$$. I apologize for replying when she was talking to you; I misread the post.

15. hba

@sylinan $\frac{ 1 }{ 3 }(2x-8)=4$ Multiply both sides by 3.

16. hba

$3 \times\frac { 1 }{ 3 }(2x-8)=4 \times 3$

17. hba

@sylinan I know you can do it now :)

18. sylinan

@hba okay so far i got 3(2x-8)=12

19. hba

Now see this $\ \cancel 3 \times \frac{ 1 }{\ \cancel 3 }(2x-8)=4 \times 3$

20. sylinan

so then its 1(2x-8)=12?

21. hba

Now add both sides by 8

22. sylinan

i thought i was suposed to do distribute the one?

23. hba

It doesn't make a diff It will stay the same :)

24. sylinan

true okay so i got x=10?

25. hba

Yeaahhhh :D

26. hba

You are right :P

27. sylinan

thank you (: help me with one more?(:

28. hba

29. sylinan

okay so open a new question?

30. hba

Yeah. The CoC says that not me :P

31. sylinan

oh okay (: