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3siny sqtcosy dy
\[\int\limits_{}^{}3\sin y \sqrt{cosy} \]
substitute u = cos(y), du = -sin(y) dy

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Other answers:

yup i did i am getting \[-3\sqrt{cosy}\]
but cos(y) is u.
\[ \int -3\sqrt{u} du \]is a pretty easy integral.
|dw:1357088383865:dw|
see i am getting <-3 {sqrtcosy}/>
\[-3 {\sqrt cosy}\]
I reiterate that cos(y) is just u.
so that is -3 sqrt(u)
yes thats what i did -3 sqrt(u) and before we said u=cosx so i rewrote it back
is that right answer for this question 3siny sqtcosy dy
No. After your substitution the integral becomes \[ \int -3 \sqrt{u} du\] you need to integrate this, which you should be able to do in two seconds. Then, you can replace all the u's with cos(y)'s and then you'll be done.
jemurray3 is correct, just think of the square root as u^1/2 i think thats what your having trouble with
-2u^(3/2)
thx

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