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ksaimouli Group Title

integratebb

  • one year ago
  • one year ago

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  1. ksaimouli Group Title
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    3siny sqtcosy dy

    • one year ago
  2. ksaimouli Group Title
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    \[\int\limits_{}^{}3\sin y \sqrt{cosy} \]

    • one year ago
  3. Jemurray3 Group Title
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    substitute u = cos(y), du = -sin(y) dy

    • one year ago
  4. ksaimouli Group Title
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    yup i did i am getting \[-3\sqrt{cosy}\]

    • one year ago
  5. Jemurray3 Group Title
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    but cos(y) is u.

    • one year ago
  6. Jemurray3 Group Title
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    \[ \int -3\sqrt{u} du \]is a pretty easy integral.

    • one year ago
  7. ksaimouli Group Title
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    |dw:1357088383865:dw|

    • one year ago
  8. ksaimouli Group Title
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    see i am getting <-3 {sqrtcosy}/>

    • one year ago
  9. ksaimouli Group Title
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    \[-3 {\sqrt cosy}\]

    • one year ago
  10. Jemurray3 Group Title
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    I reiterate that cos(y) is just u.

    • one year ago
  11. Jemurray3 Group Title
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    so that is -3 sqrt(u)

    • one year ago
  12. ksaimouli Group Title
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    yes thats what i did -3 sqrt(u) and before we said u=cosx so i rewrote it back

    • one year ago
  13. ksaimouli Group Title
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    is that right answer for this question 3siny sqtcosy dy

    • one year ago
  14. Jemurray3 Group Title
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    No. After your substitution the integral becomes \[ \int -3 \sqrt{u} du\] you need to integrate this, which you should be able to do in two seconds. Then, you can replace all the u's with cos(y)'s and then you'll be done.

    • one year ago
  15. MrDoe Group Title
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    jemurray3 is correct, just think of the square root as u^1/2 i think thats what your having trouble with

    • one year ago
  16. ksaimouli Group Title
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    -2u^(3/2)

    • one year ago
  17. ksaimouli Group Title
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    thx

    • one year ago
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