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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
3siny sqtcosy dy
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}3\sin y \sqrt{cosy} \]
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.1
substitute u = cos(y), du = sin(y) dy
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
yup i did i am getting \[3\sqrt{cosy}\]
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.1
but cos(y) is u.
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.1
\[ \int 3\sqrt{u} du \]is a pretty easy integral.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1357088383865:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
see i am getting <3 {sqrtcosy}/>
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[3 {\sqrt cosy}\]
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.1
I reiterate that cos(y) is just u.
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.1
so that is 3 sqrt(u)
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
yes thats what i did 3 sqrt(u) and before we said u=cosx so i rewrote it back
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
is that right answer for this question 3siny sqtcosy dy
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.1
No. After your substitution the integral becomes \[ \int 3 \sqrt{u} du\] you need to integrate this, which you should be able to do in two seconds. Then, you can replace all the u's with cos(y)'s and then you'll be done.
 one year ago

MrDoe Group TitleBest ResponseYou've already chosen the best response.0
jemurray3 is correct, just think of the square root as u^1/2 i think thats what your having trouble with
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
2u^(3/2)
 one year ago
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