Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

lukea

  • one year ago

I'm baffled by P-set 1G-5(b). I've checked the answer and can't make sense of it. 1. I don't see how all terms but the one provided contain a 0-factor. 2. I don't understand the reasoning behind the following: "If u =x^p, then u^p = p!" Does the p here refer only to the pth derivative of u, or also to the pth power of x? FWIW, I calculated the third derivative of 1G-5(a), and found the following. (The 3rd derivative is not given in the solution sheet.): y''' = u'''v + 3u''v' + 3u'v'' +uv''' Thank you!

  • This Question is Closed
  1. van1234
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah the notation is a little bit funky here. \[u = x ^{p}\] is just a function u where p is just an exponent. The other one which is: \[u ^{(p)}\] (notice the parentheses) Basically means that you are taking the derivative of the function u, p times. The higher derivatives are surrounded by ( ) so you can distinguish them from just normal exponents. And from the looks of it, you third derivative looks good.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.