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itsjustme_lol

  • one year ago

solving a radical equation

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  1. itsjustme_lol
    • one year ago
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  2. itsmylife
    • one year ago
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    2x+15=5 2x=-10 x=-5, just square on both sides

  3. itsjustme_lol
    • one year ago
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    what about this one?

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  4. HELP!!!!
    • one year ago
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    -5

  5. itsjustme_lol
    • one year ago
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    which one were you referring too? @HELP!!!!

  6. HELP!!!!
    • one year ago
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    the first one

  7. Schrodinger
    • one year ago
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    Hey, @itsjustme_lol. Given your second equation, \[-5\sqrt{x-9} - 7 = 23\]Since you're dealing with integers that can be divided and multiplied by each other and still result in even integers, it doesn't have to get nasty. <*hint* So, do you have any clue as to do next?

  8. itsjustme_lol
    • one year ago
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    x = -6 this is the answer i came up with

  9. Schrodinger
    • one year ago
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    Okay. Just to get a general idea of how you think and to make things easier for the future, let's say we have \[2\sqrt{x + 4} - 4 = 8\]What would be the first thing you would do, given a square root times something, and two numbers that can be added together?

  10. Schrodinger
    • one year ago
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    Ugh. I don't want to get bogged down, nevermind. Okay, so just as a general idea, if you ever have a square root with multiple terms that's being multiplied something, and you can't just square everything without anything getting "ugly" because of how squaring stuff might affect other numbers, almost always, the best thing for you to do is add like terms. In your problem, it would be adding negative seven to the side with twenty-three. Then you would get thirty. From this point, you have a square root with a coefficient, and all of that equals 30. From there, you can divide by that coefficient, and then square everything. Then you can solve for x.

  11. itsjustme_lol
    • one year ago
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    so x=45?

  12. Schrodinger
    • one year ago
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    Yes!

  13. itsjustme_lol
    • one year ago
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    thanks :D

  14. Schrodinger
    • one year ago
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    Np dude.

  15. mathstudent55
    • one year ago
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    |dw:1357102459337:dw|

  16. Schrodinger
    • one year ago
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    Oh, crap. You're right. I totally missed that.

  17. itsjustme_lol
    • one year ago
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    thankyou

  18. mathstudent55
    • one year ago
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    Np, I'm glad I caught it.

  19. Schrodinger
    • one year ago
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    Pardon me about that, @itsjustme_lol.

  20. mathstudent55
    • one year ago
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    Also, whenever you square both sides of an equation, you must check every solution bec squaring both sides can introduce extraneous solutions.

  21. itsjustme_lol
    • one year ago
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    its ok! at least you know that you made a mistke

  22. itsjustme_lol
    • one year ago
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    http://openstudy.com/study#/updates/50e3b381e4b028291d74c423

  23. HELP!!!!
    • one year ago
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    lol thats why it "open" study

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