## itsjustme_lol Group Title solving a radical equation one year ago one year ago

1. itsjustme_lol Group Title

2. itsmylife Group Title

2x+15=5 2x=-10 x=-5, just square on both sides

3. itsjustme_lol Group Title

4. HELP!!!! Group Title

-5

5. itsjustme_lol Group Title

which one were you referring too? @HELP!!!!

6. HELP!!!! Group Title

the first one

7. Schrodinger Group Title

Hey, @itsjustme_lol. Given your second equation, $-5\sqrt{x-9} - 7 = 23$Since you're dealing with integers that can be divided and multiplied by each other and still result in even integers, it doesn't have to get nasty. <*hint* So, do you have any clue as to do next?

8. itsjustme_lol Group Title

x = -6 this is the answer i came up with

9. Schrodinger Group Title

Okay. Just to get a general idea of how you think and to make things easier for the future, let's say we have $2\sqrt{x + 4} - 4 = 8$What would be the first thing you would do, given a square root times something, and two numbers that can be added together?

10. Schrodinger Group Title

Ugh. I don't want to get bogged down, nevermind. Okay, so just as a general idea, if you ever have a square root with multiple terms that's being multiplied something, and you can't just square everything without anything getting "ugly" because of how squaring stuff might affect other numbers, almost always, the best thing for you to do is add like terms. In your problem, it would be adding negative seven to the side with twenty-three. Then you would get thirty. From this point, you have a square root with a coefficient, and all of that equals 30. From there, you can divide by that coefficient, and then square everything. Then you can solve for x.

11. itsjustme_lol Group Title

so x=45?

12. Schrodinger Group Title

Yes!

13. itsjustme_lol Group Title

thanks :D

14. Schrodinger Group Title

Np dude.

15. mathstudent55 Group Title

|dw:1357102459337:dw|

16. Schrodinger Group Title

Oh, crap. You're right. I totally missed that.

17. itsjustme_lol Group Title

thankyou

18. mathstudent55 Group Title

Np, I'm glad I caught it.

19. Schrodinger Group Title

Pardon me about that, @itsjustme_lol.

20. mathstudent55 Group Title

Also, whenever you square both sides of an equation, you must check every solution bec squaring both sides can introduce extraneous solutions.

21. itsjustme_lol Group Title

its ok! at least you know that you made a mistke

22. itsjustme_lol Group Title
23. HELP!!!! Group Title

lol thats why it "open" study