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itsjustme_lol Group Title

solving a radical equation

  • one year ago
  • one year ago

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  1. itsjustme_lol Group Title
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    • one year ago
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  2. itsmylife Group Title
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    2x+15=5 2x=-10 x=-5, just square on both sides

    • one year ago
  3. itsjustme_lol Group Title
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    what about this one?

    • one year ago
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  4. HELP!!!! Group Title
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    -5

    • one year ago
  5. itsjustme_lol Group Title
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    which one were you referring too? @HELP!!!!

    • one year ago
  6. HELP!!!! Group Title
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    the first one

    • one year ago
  7. Schrodinger Group Title
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    Hey, @itsjustme_lol. Given your second equation, \[-5\sqrt{x-9} - 7 = 23\]Since you're dealing with integers that can be divided and multiplied by each other and still result in even integers, it doesn't have to get nasty. <*hint* So, do you have any clue as to do next?

    • one year ago
  8. itsjustme_lol Group Title
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    x = -6 this is the answer i came up with

    • one year ago
  9. Schrodinger Group Title
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    Okay. Just to get a general idea of how you think and to make things easier for the future, let's say we have \[2\sqrt{x + 4} - 4 = 8\]What would be the first thing you would do, given a square root times something, and two numbers that can be added together?

    • one year ago
  10. Schrodinger Group Title
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    Ugh. I don't want to get bogged down, nevermind. Okay, so just as a general idea, if you ever have a square root with multiple terms that's being multiplied something, and you can't just square everything without anything getting "ugly" because of how squaring stuff might affect other numbers, almost always, the best thing for you to do is add like terms. In your problem, it would be adding negative seven to the side with twenty-three. Then you would get thirty. From this point, you have a square root with a coefficient, and all of that equals 30. From there, you can divide by that coefficient, and then square everything. Then you can solve for x.

    • one year ago
  11. itsjustme_lol Group Title
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    so x=45?

    • one year ago
  12. Schrodinger Group Title
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    Yes!

    • one year ago
  13. itsjustme_lol Group Title
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    thanks :D

    • one year ago
  14. Schrodinger Group Title
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    Np dude.

    • one year ago
  15. mathstudent55 Group Title
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    |dw:1357102459337:dw|

    • one year ago
  16. Schrodinger Group Title
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    Oh, crap. You're right. I totally missed that.

    • one year ago
  17. itsjustme_lol Group Title
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    thankyou

    • one year ago
  18. mathstudent55 Group Title
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    Np, I'm glad I caught it.

    • one year ago
  19. Schrodinger Group Title
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    Pardon me about that, @itsjustme_lol.

    • one year ago
  20. mathstudent55 Group Title
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    Also, whenever you square both sides of an equation, you must check every solution bec squaring both sides can introduce extraneous solutions.

    • one year ago
  21. itsjustme_lol Group Title
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    its ok! at least you know that you made a mistke

    • one year ago
  22. itsjustme_lol Group Title
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    http://openstudy.com/study#/updates/50e3b381e4b028291d74c423

    • one year ago
  23. HELP!!!! Group Title
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    lol thats why it "open" study

    • one year ago
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