A community for students.
Here's the question you clicked on:
 0 viewing
Ruchi.
 2 years ago
calculate the molarity & normality of a solution containing 0.5gm of NAOH dissloved in 500ml solution.
Ruchi.
 2 years ago
calculate the molarity & normality of a solution containing 0.5gm of NAOH dissloved in 500ml solution.

This Question is Closed

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0@DLS ,@sauravshakya @saifoo.khan

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE Molarity=\frac{Number \of\moles}{Volume}\]

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0Can you calculate the number of moles of NaOH in 0.5 grams?

Australopithecus
 2 years ago
Best ResponseYou've already chosen the best response.0Molarity = \[Molarity = \frac{Moles}{LitresOfSolution}\] Normality is used to express acid/base equivalents, so it is referring to the amount of H+ or OH that can be released from a single molecule, so it is not looking at the molecule as a whole. This is useful for acid base titrations and other reactions. We use this equation to find Normality \[Normality = Molarity(Equivalents)\] To figure out Normality you simply need to divide by equivalents. EXAMPLES: So just say you have 1M of HCl, it has an equivalency of 1 because 1mole of HCl gives 1mole of H+ so, 1M*1equivilant = 1N So just say you have 2M of H2SO4, it has an equivalency of 2 because 1mole of H2SO4 can give off 2mole of H+ so, 4M*2equivialents = 4N So just say you had 4M of H3PO4, it has an equivalency of 3 because 1mole of H3PO4 can give off 3mole of H+ so, 4M*3equivalents = 12N Hope this helps if you have any questions feel free to ask
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.