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calculate the molarity & normality of a solution containing 0.5gm of NAOH dissloved in 500ml solution.
 one year ago
 one year ago
calculate the molarity & normality of a solution containing 0.5gm of NAOH dissloved in 500ml solution.
 one year ago
 one year ago

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Ruchi.Best ResponseYou've already chosen the best response.0
@DLS ,@sauravshakya @saifoo.khan
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\LARGE Molarity=\frac{Number \of\moles}{Volume}\]
 one year ago

DLSBest ResponseYou've already chosen the best response.0
Can you calculate the number of moles of NaOH in 0.5 grams?
 one year ago

AustralopithecusBest ResponseYou've already chosen the best response.0
Molarity = \[Molarity = \frac{Moles}{LitresOfSolution}\] Normality is used to express acid/base equivalents, so it is referring to the amount of H+ or OH that can be released from a single molecule, so it is not looking at the molecule as a whole. This is useful for acid base titrations and other reactions. We use this equation to find Normality \[Normality = Molarity(Equivalents)\] To figure out Normality you simply need to divide by equivalents. EXAMPLES: So just say you have 1M of HCl, it has an equivalency of 1 because 1mole of HCl gives 1mole of H+ so, 1M*1equivilant = 1N So just say you have 2M of H2SO4, it has an equivalency of 2 because 1mole of H2SO4 can give off 2mole of H+ so, 4M*2equivialents = 4N So just say you had 4M of H3PO4, it has an equivalency of 3 because 1mole of H3PO4 can give off 3mole of H+ so, 4M*3equivalents = 12N Hope this helps if you have any questions feel free to ask
 one year ago
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