Here's the question you clicked on:
guess
dy/dx=(x+y)/xy
i would have substituted x=vy any method specifically asked for ?
\[\frac{dy}{dx} = \frac{x+y}{xy}\] homegeneous equation y = uv \[\frac{dy}{dx} = \frac{x/x + y/x}{y/x} => \frac{dy}{dx} = \frac{1+y/x}{y/x}\] \(y=ux\) \[\frac{dy}{dx} = v+ \frac{dx}{dx}x\]
@Mimi_x3 is confused with 'u' and 'v' :P
\[\frac{dy}{dx} = \frac{1+u}{u}\]
\(\huge u+x\frac{du}{dx}=\frac{1+u}{u}\) this is variable separable and hence easily solvable.