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Mimi_x3

  • 2 years ago

Just for fun. :) \[\int_{0}^{\pi/2}xcot(x)dx\]

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  1. hartnn
    • 2 years ago
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    is the answer \(\pi^3\)/24 ???

  2. hartnn
    • 2 years ago
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    square root of that

  3. Mimi_x3
    • 2 years ago
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    Nope!!!

  4. Mimi_x3
    • 2 years ago
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    It cannot be that easy!!

  5. hba
    • 2 years ago
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    (1/2) pi ln(2)

  6. hartnn
    • 2 years ago
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    oh, yes... \(I=\int_{0}^{\pi/2}x\cot(x)dx \\I=\int_{0}^{\pi/2}(\pi/2-x)\tan(x)dx\) now multiply both equations to eliminate trignometric function

  7. hba
    • 2 years ago
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    @Mimi_x3 Please respond.

  8. hartnn
    • 2 years ago
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    hba, your answer is correct.

  9. hartnn
    • 2 years ago
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    did u integrate by parts

  10. Mimi_x3
    • 2 years ago
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    Soryy!! Faster than expected!! I think @hba cheated :)

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  11. hartnn
    • 2 years ago
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    you think ? i know :P

  12. hba
    • 2 years ago
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    I did not solve it guys.

  13. hba
    • 2 years ago
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    Some one else solved it for me.

  14. hba
    • 2 years ago
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    :P

  15. Mimi_x3
    • 2 years ago
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    It was obv :P impossible to solve it in a couple of seconds.

  16. hartnn
    • 2 years ago
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    oh, the catch was to add, not multiply :P hba, wolf.

  17. hba
    • 2 years ago
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    Yes @hartnn Yes :P

  18. hba
    • 2 years ago
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    @Callisto Why did you not comment ?

  19. Callisto
    • 2 years ago
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    My comment... @hartnn @Mimi_x3 ♥♥♥

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