A community for students.
Here's the question you clicked on:
 0 viewing
Accipiter46
 3 years ago
Please explain this to me:
\[\frac{1}{2}\int_{b1/2}^{b+1/2}\frac{1}{\sqrt{x}}dx=\]
\[\frac{1}{2}\int_{b1/2}^{0}\frac{1}{\sqrt{x}}dx+\frac{1}{2}\int_{0}^{b+1/2}\frac{1}{\sqrt{x}}dx=\]
\[\sqrt{1/2b}+\sqrt{1/2+b}\]
Accipiter46
 3 years ago
Please explain this to me: \[\frac{1}{2}\int_{b1/2}^{b+1/2}\frac{1}{\sqrt{x}}dx=\] \[\frac{1}{2}\int_{b1/2}^{0}\frac{1}{\sqrt{x}}dx+\frac{1}{2}\int_{0}^{b+1/2}\frac{1}{\sqrt{x}}dx=\] \[\sqrt{1/2b}+\sqrt{1/2+b}\]

This Question is Closed

BluFoot
 3 years ago
Best ResponseYou've already chosen the best response.0This is the fundamental theorem of calculus. Check out this video, there's an example similar to yours at 6:00 http://www.youtube.com/watch?v=PGmVvIglZx8

Accipiter46
 3 years ago
Best ResponseYou've already chosen the best response.0oh, also: \[0\le b \le1/2\]

Accipiter46
 3 years ago
Best ResponseYou've already chosen the best response.0Thx, I'll take a look.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0also \[\int_a^bf(x)dx=\int_a^cf(x)dx+\int_c^bf(x)dx\] is always true

Accipiter46
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, I get the first part. What happens when the integrals are calculated?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0\(\int_a^bf(x)dx=\int_a^cf(x)dx+\int_c^bf(x)dx\) true if \(a \le c \le b\)

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0actually it is always true, so long as the integral exists
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.