Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Ruchi.

  • one year ago

how many kilogram of wet NaOH containing 12% water are required to prepare 60 litre of 0.50 N solution?

  • This Question is Closed
  1. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @DLS @skullpatrol @satellite73

  2. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hlp me out

  3. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    calculate no. of moles

  4. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    60 litre of 0.50 N solution?

  5. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  6. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i mean calculate no.of moles in 60 litre of 0.50 N solution

  7. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    answer is nt coming ?

  8. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @DLS

  9. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    idk it has to be done that way only calculate no. of moles from latter info and put that value in n=g/m

  10. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hav u did it

  11. Ruchi.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @surdawi

  12. surdawi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1L OF 0.50 N of NaOH requires NaOH = 20g 60 L of 0.50 NaOH requires NaOH = 20 x 60= 1200 g = 1.2 kg. 88 g NaOH is obtained from wet sample = 100g therefore 1 kg of NaOH is obtained from a wet sample 100/88 x 1.2= 1.364 kg

  13. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.