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Ruchi.

  • 3 years ago

how many kilogram of wet NaOH containing 12% water are required to prepare 60 litre of 0.50 N solution?

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  1. Ruchi.
    • 3 years ago
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    @DLS @skullpatrol @satellite73

  2. Ruchi.
    • 3 years ago
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    hlp me out

  3. DLS
    • 3 years ago
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    calculate no. of moles

  4. DLS
    • 3 years ago
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    60 litre of 0.50 N solution?

  5. Ruchi.
    • 3 years ago
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    yes

  6. DLS
    • 3 years ago
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    i mean calculate no.of moles in 60 litre of 0.50 N solution

  7. Ruchi.
    • 3 years ago
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    answer is nt coming ?

  8. Ruchi.
    • 3 years ago
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    @DLS

  9. DLS
    • 3 years ago
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    idk it has to be done that way only calculate no. of moles from latter info and put that value in n=g/m

  10. Ruchi.
    • 3 years ago
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    hav u did it

  11. Ruchi.
    • 3 years ago
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    @surdawi

  12. surdawi
    • 3 years ago
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    1L OF 0.50 N of NaOH requires NaOH = 20g 60 L of 0.50 NaOH requires NaOH = 20 x 60= 1200 g = 1.2 kg. 88 g NaOH is obtained from wet sample = 100g therefore 1 kg of NaOH is obtained from a wet sample 100/88 x 1.2= 1.364 kg

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