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jacksonjrrodney Group Title

Alg 2 help Use the Rational Root Theorem to list all possible rational roots of 3x3 + x2 – 15x – 5 = 0. Then find any actual rational roots. Find the roots of 10x4 + x3 + 7x2 + x – 3 = 0 A polynomial equation with rational coefficients has the roots Sq rt of 7 and –5i. Find two additional roots Find a third-degree polynomial equation with integer coefficients that has the roots 8 and 3i.

  • one year ago
  • one year ago

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  1. swe100 Group Title
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    The rational root theorem states that any rational root of a polynomial will be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient. The leading coefficient is 10, so the factors are -10, -5, -2, -1, 1, 2, 5, and 10. The constant term is -3, so the factors are -3, -1, 1, and 3. The possible rational roots are -3/10, -1/10, -3/5, -1/5, -3/2, -1/2, -3/1, -1/1, 1/1, 3/1, 1/2, 3/2, 1/5, 3/5, 1/10, and 3/10.

    • one year ago
  2. jacksonjrrodney Group Title
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    can you be more clear i still dont know the answer

    • one year ago
  3. swe100 Group Title
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    I listed a big list of fractions at the end, those are all the possible roots from the rational root theorem. (I know, it's a big list)

    • one year ago
  4. swe100 Group Title
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    Oh oops I found the roots of the wrong equation

    • one year ago
  5. swe100 Group Title
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    The leading coefficient is 3 and the constant term is -5, so the roots are -5/3, -5/1, -1/1, 1/1, 5/1, and 5/3

    • one year ago
  6. jacksonjrrodney Group Title
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    which number is this, one right?

    • one year ago
  7. jacksonjrrodney Group Title
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    @sauravshakya do you understand this??

    • one year ago
  8. precal Group Title
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    you should post your questions one at a time because it will be confusing for you to understand our postings

    • one year ago
  9. julliemyers Group Title
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    what unit and lesson?

    • one year ago
  10. jacksonjrrodney Group Title
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    Theorems About Roots of Polynomial Equations

    • one year ago
  11. julliemyers Group Title
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    1. Use the Rational Root Theorem to list all possible rational roots of the polynomial equation x3 – x2 – x – 3 = 0. Do not find the actual roots. (1 point) (1 pt) –3, –1, 1, 3 (0 pts) 1, 3 (0 pts) –33 (0 pts) no roots 1 /1 point This item has been reviewed and is scheduled to be updated. All students will receive full credit for any response to the following. 2. Find the roots of the polynomial equation. 2x3 + 2x2 – 19x + 20 = 0 (1 point) (1 pt) , , –4 (1 pt) , , 4 (1 pt) , , –4 (1 pt) , , 4 1 /1 point 3. A cubic polynomial with rational coefficients has the roots 6 +and . Find one additional root. (1 point) (0 pts) –6 – (0 pts) 6 + (0 pts) –6 + (1 pt) 6 – 0 /1 point 4. Find a third-degree polynomial equation with rational coefficients that has roots –4 and 6 + i. (1 point) (1 pt) x3 – 8x2 – 11x + 148 = 0 (0 pts) x3 – 8x2 – 12x + 37 = 0 (0 pts) x3 – 12x2 + 37x = 0 (0 pts) x3 – 8x2 – 11x = 0 1 /1 point 5. What does Descartes's Rule of Signs tell you about the real roots of the polynomial? –2x3 + 3x2 – 5x – 2 = 0 (1 point) (0 pts) There is one positive root and either 2 or 0 negative roots. (0 pts) There are either 2 or 0 positive roots and there are either 2 or 0 negative roots. (0 pts) There is one positive root and one negative root. (1 pt) There are either 2 or 0 positive roots and one negative root. 0 /1 point

    • one year ago
  12. jacksonjrrodney Group Title
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    no i think its unit 6 lesson 5 it only has four questions

    • one year ago
  13. julliemyers Group Title
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    1. What is the solution of the equation? –9 = –7 (1 point) (1 pt) –6 (0 pts) 4 (0 pts) 14 (0 pts) –8 1 /1 point 2. What is the solution of the equation? – 5 = 59 (1 point) (1 pt) –5, 11 (0 pts) 5 (0 pts) 11 (0 pts) –11 1 /1 point 3. The area of a circular trampoline is 108.94 square feet. What is the radius of the trampoline? Round to the nearest hundredth. (1 point) (0 pts) 10.44 feet (1 pt) 5.89 feet (0 pts) 34.68 feet (0 pts) 3.32 feet 1 /1 point 4. What is the solution of the equation? 5x = (1 point) (0 pts) –1 (0 pts) 1 and (1 pt) 1 (0 pts) 1 /1 point 5. What is the solution of – = 5 ? (1 point) (0 pts) x = 0 (0 pts) x = 16 and x = 0 (1 pt) x = 16 (0 pts) x = 16 and x = 1 1 /1 point

    • one year ago
  14. jacksonjrrodney Group Title
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    lol its the same questions as the questions listed

    • one year ago
  15. julliemyers Group Title
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    hhmmm idk, i cant find em

    • one year ago
  16. jacksonjrrodney Group Title
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    its ok thank you

    • one year ago
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