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Solmyr

  • 3 years ago

Factor completely: 18x2 − 21x − 15 3(2x + 1)(3x − 5) 3(2x − 5)(3x + 1) 3(2x − 1)(3x + 5) 3(6x + 1)(x − 5)

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  1. swe100
    • 3 years ago
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    First, factor out the constant of 3 to get \[3(x^2-7x-5)\]

  2. Solmyr
    • 3 years ago
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    ok

  3. swe100
    • 3 years ago
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    Then factor x^2-7x-5

  4. swe100
    • 3 years ago
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    i mean 6x^2-7x-5

  5. Solmyr
    • 3 years ago
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    36x - 7x - 5

  6. swe100
    • 3 years ago
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    Then you will get \[3(2x+1)(3x-5)\]

  7. Solmyr
    • 3 years ago
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    oh

  8. Solmyr
    • 3 years ago
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    thank you

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