Solmyr
Factor completely: 18x2 − 21x − 15
3(2x + 1)(3x − 5)
3(2x − 5)(3x + 1)
3(2x − 1)(3x + 5)
3(6x + 1)(x − 5)



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swe100
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First, factor out the constant of 3 to get \[3(x^27x5)\]

Solmyr
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ok

swe100
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Then factor x^27x5

swe100
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i mean 6x^27x5

Solmyr
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36x  7x  5

swe100
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Then you will get \[3(2x+1)(3x5)\]

Solmyr
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oh

Solmyr
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thank you