Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

***Help Request*** ***Medal &/or Fan Awarded to best helper*** Use two variables. One number is 4 less than 3 times another number. If their sum is 16, find the numbers.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

Let the 2 numbers be 'x' and 'y' . heir sum is 16----> x+y=16 got this ?
One number is 4 less than 3 times another number. --->x+4=3y
@minnie123 you there ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yeah i am trying to comprehend what you're asking me to do... a little confused
did u get how i got the 2 equations ?? x+y=16 x+4=3y ??
Let the first no. be \(x\) & other be \(y\). Now, according to question:- x+y=16 ....... (i) also y=3x-4 Now put the value of 'y' in first equation & you got :- x+3x-4=16 4x-4=16 Take 4 as common :- 4(x-4)=16 x-4=16/4=4 x=8 Therefore y=8 because x+y=16 8+y=16 y=16-8=8
ok so i kinda understand Viper because he visually showed me... i wont understand easily unlessi have it kinda mapped out already..
will you be able to do other similar question by yourself ???
idk... maybe...

Not the answer you are looking for?

Search for more explanations.

Ask your own question