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themonkey

  • 3 years ago

How do you find the y-intercept of h(x) in h(x)=x^2-16/x-4?

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  1. hartnn
    • 3 years ago
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    to find the y-intercept , put x=0 in that equation, what you get ?

  2. themonkey
    • 3 years ago
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    But how does it work when one function is over the other one?

  3. hartnn
    • 3 years ago
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    just put x=0 in that equation!

  4. themonkey
    • 3 years ago
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    So I put it in both of them

  5. hartnn
    • 3 years ago
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    yes, h(0) = (0-16)/(0-4) =.... ?

  6. themonkey
    • 3 years ago
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    (0,4)

  7. hartnn
    • 3 years ago
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    thas your y-intercept, correct! :)

  8. themonkey
    • 3 years ago
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    Okay thank you that helped alot

  9. hartnn
    • 3 years ago
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    welcome ^_^

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