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anonymous
 4 years ago
*help requested*
*fan and medal awarded*
Solve for y: 2/3y + 8 = 6
y = 3
y = 5
y = 3
y = 5
The set of ordered pairs below defines a relation. In each ordered pair (x, y), x represents the daily wages of a plumber, and y represents the daily wages of her assistant.
{(144, 72), (171, 84), (198, 84), (171, 96), (144, 72)}
What is the difference between the values of the least and greatest elements in the domain of this relation?
24
54
72
126
anonymous
 4 years ago
*help requested* *fan and medal awarded* Solve for y: 2/3y + 8 = 6 y = 3 y = 5 y = 3 y = 5 The set of ordered pairs below defines a relation. In each ordered pair (x, y), x represents the daily wages of a plumber, and y represents the daily wages of her assistant. {(144, 72), (171, 84), (198, 84), (171, 96), (144, 72)} What is the difference between the values of the least and greatest elements in the domain of this relation? 24 54 72 126

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey are you the same girl as the pic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because your very pretty

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes lol but i need help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need help. not a convo. if u want to talk msg me.

matt101
 4 years ago
Best ResponseYou've already chosen the best response.1For the first question, if y is part of the denominator, I get 1/3 which isn't an option. I'm assuming it's (2/3)y + 8 = 6 meaning: (2/3)y = 2 y = 3 For your second question, the domain refers to the x coordinate in each ordered pair, so the difference between the greatest and least would be 198  144 = 54.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0#1C.y=3(i know) #2C.72(i think)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0uhm well @Torrayani<3 , @matt101 did the work so ima give the medal to him. plus u got the second one wrong.
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