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xoalyssaxo1
Hi, I just have two questions if you could help by explaining to me so I can finish them it'd be wonderful! If quadrilateral BDMZ is a rhombus, which of the following ordered pairs could be a vertex? Segment BD is shown on the coordinate plane. Point B is at -3, 9; and point D is at -7, 2. (1, -1) (2, 3) (1, 3) (2, 2)
f quadrilateral FGHI is an isosceles trapezoid, what is the ordered pair of its missing vertex? http://gyazo.com/97b3198363e9fd8b091cf0bde1fa9200 (9, 1) (6, 1) (10, 1) (7, 1)
For the second one I have 9,1
For this ques If quadrilateral BDMZ is a rhombus, which of the following ordered pairs could be a vertex? Segment BD is shown on the coordinate plane. Point B is at -3, 9; and point D is at -7, 2. First find distance of BD using distance formula \[D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
As you get this you can use distance formula from points B and D Because your unknowns are at the same distance .
One of them is at the same distance so we will be using distance formula on your options The option in which you get a similar distance kaboom it is solved :D
Sorry openstudy is being very slow and not loading and I got 9,1 because I tested to see which made the figure and 9,1 and 10,1 did but 10,1 looks even not isocles.
I used the distance formula and got 8 but how does that make two points @hba
I guess it is (10,1) The distance BD is \[\sqrt{65}\]
Now take one of your options A)(1, -1) Check its distance from B(-3,9) and then Check its distance from D(-7,2) If one of them is at the same distance as BD then this option is correct. If not move on to the other options B)(2, 3) C)(1, 3) D)(2, 2)