Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

scottmanBest ResponseYou've already chosen the best response.1
I got 2/3(x^3/2)+2(x^1/2)+C however it is stated to be wrong
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
Can you show me how you got to that result?
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
P.S. It's almost correct.
 one year ago

scottmanBest ResponseYou've already chosen the best response.1
Sure x^1/2 + 1/4 x^1/2 (x^3/2)/(3/2)+(1/4)(x^1/2)/(1/2)
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
That looks good to me. Now what is \[\Large \frac{1/4}{1/2}?\]
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
Almost. \[\Large \frac{1/4}{1/2}=\frac{2}{4}=\frac{1}{2}\]In general, \[\Large \frac{a/b}{c/d}=\frac{ad}{bc}\]
 one year ago

scottmanBest ResponseYou've already chosen the best response.1
so then instead of the 2√x its 1/2√x?
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
That looks right to me.
 one year ago

scottmanBest ResponseYou've already chosen the best response.1
ok 2/3(x^3/2)+1/2(x^1/2) is the correct answer?
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
With a +C at the end.
 one year ago

scottmanBest ResponseYou've already chosen the best response.1
Always forget the C, thanks a lot you were a really big help. You truly are the king.
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
You're welcome, and thanks :P
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.