scottman
How do I find the indefinite integral of:
∫(√x) + (1/(4√x))



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scottman
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I got 2/3(x^3/2)+2(x^1/2)+C however it is stated to be wrong

KingGeorge
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Can you show me how you got to that result?

KingGeorge
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P.S. It's almost correct.

scottman
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Sure
x^1/2 + 1/4 x^1/2
(x^3/2)/(3/2)+(1/4)(x^1/2)/(1/2)

scottman
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Am I missing a step?

KingGeorge
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That looks good to me. Now what is \[\Large \frac{1/4}{1/2}?\]

scottman
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2

KingGeorge
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Almost. \[\Large \frac{1/4}{1/2}=\frac{2}{4}=\frac{1}{2}\]In general, \[\Large \frac{a/b}{c/d}=\frac{ad}{bc}\]

scottman
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ah careless mistake

scottman
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so then instead of the 2√x its 1/2√x?

KingGeorge
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That looks right to me.

scottman
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ok 2/3(x^3/2)+1/2(x^1/2) is the correct answer?

KingGeorge
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With a +C at the end.

scottman
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Always forget the C, thanks a lot you were a really big help. You truly are the king.

KingGeorge
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You're welcome, and thanks :P