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How do I find the indefinite integral of: ∫(√x) + (1/(4√x))

Mathematics
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I got 2/3(x^3/2)+2(x^1/2)+C however it is stated to be wrong
Can you show me how you got to that result?
P.S. It's almost correct.

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Other answers:

Sure x^1/2 + 1/4 x^-1/2 (x^3/2)/(3/2)+(1/4)(x^1/2)/(1/2)
Am I missing a step?
That looks good to me. Now what is \[\Large \frac{1/4}{1/2}?\]
2
Almost. \[\Large \frac{1/4}{1/2}=\frac{2}{4}=\frac{1}{2}\]In general, \[\Large \frac{a/b}{c/d}=\frac{ad}{bc}\]
ah careless mistake
so then instead of the 2√x its 1/2√x?
That looks right to me.
ok 2/3(x^3/2)+1/2(x^1/2) is the correct answer?
With a +C at the end.
Always forget the C, thanks a lot you were a really big help. You truly are the king.
You're welcome, and thanks :P

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