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scottman Group Title

How do I find the indefinite integral of: ∫(√x) + (1/(4√x))

  • one year ago
  • one year ago

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  1. scottman Group Title
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    I got 2/3(x^3/2)+2(x^1/2)+C however it is stated to be wrong

    • one year ago
  2. KingGeorge Group Title
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    Can you show me how you got to that result?

    • one year ago
  3. KingGeorge Group Title
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    P.S. It's almost correct.

    • one year ago
  4. scottman Group Title
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    Sure x^1/2 + 1/4 x^-1/2 (x^3/2)/(3/2)+(1/4)(x^1/2)/(1/2)

    • one year ago
  5. scottman Group Title
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    Am I missing a step?

    • one year ago
  6. KingGeorge Group Title
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    That looks good to me. Now what is \[\Large \frac{1/4}{1/2}?\]

    • one year ago
  7. scottman Group Title
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    2

    • one year ago
  8. KingGeorge Group Title
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    Almost. \[\Large \frac{1/4}{1/2}=\frac{2}{4}=\frac{1}{2}\]In general, \[\Large \frac{a/b}{c/d}=\frac{ad}{bc}\]

    • one year ago
  9. scottman Group Title
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    ah careless mistake

    • one year ago
  10. scottman Group Title
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    so then instead of the 2√x its 1/2√x?

    • one year ago
  11. KingGeorge Group Title
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    That looks right to me.

    • one year ago
  12. scottman Group Title
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    ok 2/3(x^3/2)+1/2(x^1/2) is the correct answer?

    • one year ago
  13. KingGeorge Group Title
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    With a +C at the end.

    • one year ago
  14. scottman Group Title
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    Always forget the C, thanks a lot you were a really big help. You truly are the king.

    • one year ago
  15. KingGeorge Group Title
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    You're welcome, and thanks :P

    • one year ago
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