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Goten77

  • 2 years ago

find the derivative of e=mc^2

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  1. Goten77
    • 2 years ago
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    \[e=mc ^{2}\]

  2. hba
    • 2 years ago
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    Btw, \[e \neq mc^2\]

  3. Goten77
    • 2 years ago
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    :O

  4. hba
    • 2 years ago
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    Haha lol Do we have to derivate it w.r.t c ?

  5. hartnn
    • 2 years ago
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    w.r.t which variable ?

  6. hartnn
    • 2 years ago
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    w.r.t--->with respect to

  7. Goten77
    • 2 years ago
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    hmm which ever is possible

  8. hba
    • 2 years ago
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    So i would consider d/dc

  9. hartnn
    • 2 years ago
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    c is speed of light which is constant, try 'm'

  10. hartnn
    • 2 years ago
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    de/dm is just c^2

  11. Goten77
    • 2 years ago
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    so would it b like 0=c^2

  12. sauravshakya
    • 2 years ago
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    Do u mean to derive it?

  13. hartnn
    • 2 years ago
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    does 'e' depend on 'm' if no, then de/dm=0

  14. hba
    • 2 years ago
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    de = c^2 dm

  15. Goten77
    • 2 years ago
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    |dw:1357225416723:dw|

  16. hba
    • 2 years ago
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    As c is constant c^2 is also constant :)

  17. hartnn
    • 2 years ago
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    whats the purpose of finding the derivative ?

  18. Goten77
    • 2 years ago
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    hmm im not sure... what i was thinking

  19. hba
    • 2 years ago
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    woW

  20. hartnn
    • 2 years ago
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    good.....keep it up.

  21. hartnn
    • 2 years ago
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    one day, you'll end up deriving something more significant than e=mc^2. my best wishes....

  22. hba
    • 2 years ago
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    The amount of kinetic energy it takes to cause an object to gain any amount of mass is equal to the amount of mass gained times c^2.

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