A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

hba
 2 years ago
Best ResponseYou've already chosen the best response.0Haha lol Do we have to derivate it w.r.t c ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1w.r.t>with respect to

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1hmm which ever is possible

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1c is speed of light which is constant, try 'm'

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1so would it b like 0=c^2

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0Do u mean to derive it?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1does 'e' depend on 'm' if no, then de/dm=0

hba
 2 years ago
Best ResponseYou've already chosen the best response.0As c is constant c^2 is also constant :)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1whats the purpose of finding the derivative ?

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1hmm im not sure... what i was thinking

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1one day, you'll end up deriving something more significant than e=mc^2. my best wishes....

hba
 2 years ago
Best ResponseYou've already chosen the best response.0The amount of kinetic energy it takes to cause an object to gain any amount of mass is equal to the amount of mass gained times c^2.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.