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What is the f'(x) of f(X)=sin^3x

Calculus1
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Have you attempted this one yet ?
yeah
\[f(x) = \sin ^{3}(x)\] Did I write this down correctly? If so, try substitution. For example, let u = sin(x) and then take the derivative of u^3

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Other answers:

I got f'(X) is 9x^2cosx^2
that is 3u^2
3u^2 du/dx, yes. Now what is du/dx if u = sin x?
In other words, what is u' if u = sin x
cosx^2
What is the derivative of sin(x) ?
COS
Great, so du/dx = cos x So we have 3u^2 * cos x Substitute u = sin(x) back in and what do we end up with ?
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