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How do I find a vertex or x value from y=(x-2)(x-6) ?

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You could either rewrite it in vertex form, or you could take the halfway point between the two x-intercepts. In this case, x = 2 and x = 6 are both y-intercepts. A parabola is symmetric so halfway between these points is the line of symmetry. Determine what x-value this corresponds to and then find the associated y value. These two points will be your vertex.
Thank you!
expand it out by mutiplying it and then you can use the vertex formula x=-b/2a to find the x coordinate of your vertex then sub that x value into your equation to find your y value

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^ thank you as well!

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