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zaynahf

  • 3 years ago

Find x > 3 such that ln(x) < x^(0.1)

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  1. wio
    • 3 years ago
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    My guess? \[ \ln(x) < x^{0.1} \\ \ln(x) - x^{0.1} < 0 \] Then use newton's iterative method of finding roots. They're both increasing functions.

  2. zaynahf
    • 3 years ago
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    Yeah, thats what i was thinking.. thanks!

  3. wio
    • 3 years ago
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    No problem

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