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## anonymous 3 years ago Find x > 3 such that ln(x) < x^(0.1)

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1. anonymous

My guess? $\ln(x) < x^{0.1} \\ \ln(x) - x^{0.1} < 0$ Then use newton's iterative method of finding roots. They're both increasing functions.

2. anonymous

Yeah, thats what i was thinking.. thanks!

3. anonymous

No problem

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