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What is the sum of a 6-term geometric series if the first term is 8 and the last term is 134,456 ? Answers to choose from. a)129,513 b)130,624 c)156,864 d)172,846

Mathematics
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let the first term = a then 6th term =ar^5 where r = common ration can you find r from this information?
i might need some guidance but let me try!
ok

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Other answers:

i really dont know how i got this but i ended up with 832 as the common ratio.
6tt term = 134456 = ar^5 ist term = 8 so ar^5/a = r^5 = 134456/8 = 16807
|dw:1357256722836:dw|
you can now find the sum of the 6 terms by plugging in the values of a and r into the formula sum = a * r^n - 1 ------ r - 1
ohh i see what i di wrong !! i was way off
im almost done
the value of n (number of terms) is 6
okayy i got c)156,864
right , good job
thankyou
yw

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