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ridgeboy36 Group Title

What is the sum of a 6-term geometric series if the first term is 8 and the last term is 134,456 ? Answers to choose from. a)129,513 b)130,624 c)156,864 d)172,846

  • one year ago
  • one year ago

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  1. cwrw238 Group Title
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    let the first term = a then 6th term =ar^5 where r = common ration can you find r from this information?

    • one year ago
  2. ridgeboy36 Group Title
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    i might need some guidance but let me try!

    • one year ago
  3. cwrw238 Group Title
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    ok

    • one year ago
  4. ridgeboy36 Group Title
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    i really dont know how i got this but i ended up with 832 as the common ratio.

    • one year ago
  5. cwrw238 Group Title
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    6tt term = 134456 = ar^5 ist term = 8 so ar^5/a = r^5 = 134456/8 = 16807

    • one year ago
  6. cwrw238 Group Title
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    |dw:1357256722836:dw|

    • one year ago
  7. cwrw238 Group Title
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    you can now find the sum of the 6 terms by plugging in the values of a and r into the formula sum = a * r^n - 1 ------ r - 1

    • one year ago
  8. ridgeboy36 Group Title
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    ohh i see what i di wrong !! i was way off

    • one year ago
  9. ridgeboy36 Group Title
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    im almost done

    • one year ago
  10. cwrw238 Group Title
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    the value of n (number of terms) is 6

    • one year ago
  11. ridgeboy36 Group Title
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    okayy i got c)156,864

    • one year ago
  12. cwrw238 Group Title
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    right , good job

    • one year ago
  13. ridgeboy36 Group Title
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    thankyou

    • one year ago
  14. cwrw238 Group Title
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    yw

    • one year ago
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