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ridgeboy36

  • 2 years ago

What is the sum of a 6-term geometric series if the first term is 8 and the last term is 134,456 ? Answers to choose from. a)129,513 b)130,624 c)156,864 d)172,846

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  1. cwrw238
    • 2 years ago
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    let the first term = a then 6th term =ar^5 where r = common ration can you find r from this information?

  2. ridgeboy36
    • 2 years ago
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    i might need some guidance but let me try!

  3. cwrw238
    • 2 years ago
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    ok

  4. ridgeboy36
    • 2 years ago
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    i really dont know how i got this but i ended up with 832 as the common ratio.

  5. cwrw238
    • 2 years ago
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    6tt term = 134456 = ar^5 ist term = 8 so ar^5/a = r^5 = 134456/8 = 16807

  6. cwrw238
    • 2 years ago
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    |dw:1357256722836:dw|

  7. cwrw238
    • 2 years ago
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    you can now find the sum of the 6 terms by plugging in the values of a and r into the formula sum = a * r^n - 1 ------ r - 1

  8. ridgeboy36
    • 2 years ago
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    ohh i see what i di wrong !! i was way off

  9. ridgeboy36
    • 2 years ago
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    im almost done

  10. cwrw238
    • 2 years ago
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    the value of n (number of terms) is 6

  11. ridgeboy36
    • 2 years ago
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    okayy i got c)156,864

  12. cwrw238
    • 2 years ago
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    right , good job

  13. ridgeboy36
    • 2 years ago
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    thankyou

  14. cwrw238
    • 2 years ago
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    yw

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