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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[x(x^29)\] is a start. then factor the \(x^29\) part as the difference of two squares
 one year ago

tpenn Group TitleBest ResponseYou've already chosen the best response.0
wait im confused, can you show work?
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.1
He just took out an x
 one year ago

tpenn Group TitleBest ResponseYou've already chosen the best response.0
so x(x^29) is the answer?
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.1
\[x^39x\] x is common to both sides
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.1
so then \[x(x^29)\]
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.1
But \[x^29 is factorable\]
 one year ago

tpenn Group TitleBest ResponseYou've already chosen the best response.0
how do you factor x^29 though?
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.1
Use the rule of a difference of two squares.
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.1
\[(x+3)(x3)\]
 one year ago

tpenn Group TitleBest ResponseYou've already chosen the best response.0
oh okay i understand, i was just confused at how you were explaining it, thanks
 one year ago
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