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tpenn

Factor: x^3-9x

  • one year ago
  • one year ago

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  1. satellite73
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    \[x(x^2-9)\] is a start. then factor the \(x^2-9\) part as the difference of two squares

    • one year ago
  2. tpenn
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    wait im confused, can you show work?

    • one year ago
  3. hawkfalcon
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    He just took out an x

    • one year ago
  4. tpenn
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    so x(x^2-9) is the answer?

    • one year ago
  5. hawkfalcon
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    \[x^3-9x\] x is common to both sides

    • one year ago
  6. hawkfalcon
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    so then \[x(x^2-9)\]

    • one year ago
  7. tpenn
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    ohh okay

    • one year ago
  8. hawkfalcon
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    But \[x^2-9 is factorable\]

    • one year ago
  9. tpenn
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    how do you factor x^2-9 though?

    • one year ago
  10. hawkfalcon
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    Use the rule of a difference of two squares.

    • one year ago
  11. hawkfalcon
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    \[(x+3)(x-3)\]

    • one year ago
  12. tpenn
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    oh okay i understand, i was just confused at how you were explaining it, thanks

    • one year ago
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