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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0\[x(x^29)\] is a start. then factor the \(x^29\) part as the difference of two squares

tpenn
 2 years ago
Best ResponseYou've already chosen the best response.0wait im confused, can you show work?

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.1He just took out an x

tpenn
 2 years ago
Best ResponseYou've already chosen the best response.0so x(x^29) is the answer?

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.1\[x^39x\] x is common to both sides

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.1so then \[x(x^29)\]

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.1But \[x^29 is factorable\]

tpenn
 2 years ago
Best ResponseYou've already chosen the best response.0how do you factor x^29 though?

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.1Use the rule of a difference of two squares.

tpenn
 2 years ago
Best ResponseYou've already chosen the best response.0oh okay i understand, i was just confused at how you were explaining it, thanks
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