anonymous
  • anonymous
Factor: x^3-9x
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[x(x^2-9)\] is a start. then factor the \(x^2-9\) part as the difference of two squares
anonymous
  • anonymous
wait im confused, can you show work?
hawkfalcon
  • hawkfalcon
He just took out an x

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anonymous
  • anonymous
so x(x^2-9) is the answer?
hawkfalcon
  • hawkfalcon
\[x^3-9x\] x is common to both sides
hawkfalcon
  • hawkfalcon
so then \[x(x^2-9)\]
anonymous
  • anonymous
ohh okay
hawkfalcon
  • hawkfalcon
But \[x^2-9 is factorable\]
anonymous
  • anonymous
how do you factor x^2-9 though?
hawkfalcon
  • hawkfalcon
Use the rule of a difference of two squares.
hawkfalcon
  • hawkfalcon
\[(x+3)(x-3)\]
anonymous
  • anonymous
oh okay i understand, i was just confused at how you were explaining it, thanks

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