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hawkfalconBest ResponseYou've already chosen the best response.0
\[f(x)=\left[\begin{matrix}x & x \le0 \\ x+1 & x>0\end{matrix}\right]\]
 one year ago

hawkfalconBest ResponseYou've already chosen the best response.0
find \[\int\limits_{2}^{1}xf(x)dx\]
 one year ago

wioBest ResponseYou've already chosen the best response.2
This is the discontinuous type of improper integral.
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
break in two \[\int_{2}^0+\int_0^1\]
 one year ago

wioBest ResponseYou've already chosen the best response.2
\[ \large \int\limits_{2}^{1}xf(x)dx = \lim_{t\to 0^+} \int\limits_{2}^{t}xf(x)dx + \lim_{t\to 0^} \int\limits_{t}^{1}xf(x)dx \]
 one year ago

hawkfalconBest ResponseYou've already chosen the best response.0
Okay, that makes sense. Just split into two.
 one year ago
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