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hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=\left[\begin{matrix}x & x \le0 \\ x+1 & x>0\end{matrix}\right]\]

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.0find \[\int\limits_{2}^{1}xf(x)dx\]

wio
 2 years ago
Best ResponseYou've already chosen the best response.2This is the discontinuous type of improper integral.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0break in two \[\int_{2}^0+\int_0^1\]

wio
 2 years ago
Best ResponseYou've already chosen the best response.2\[ \large \int\limits_{2}^{1}xf(x)dx = \lim_{t\to 0^+} \int\limits_{2}^{t}xf(x)dx + \lim_{t\to 0^} \int\limits_{t}^{1}xf(x)dx \]

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, that makes sense. Just split into two.
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