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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
compute all the numbers and see that they are equal
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you need \(\log(100)\) and also \(\log(10000)\) first
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if you have a power of ten , the log counts the zeros
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
lol i have no idea how to do this
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
When log 100 = a, this means: \[10^a=100\]Now, because 100 is a power of 10, you can see very quickly what log 100 is... Same for log 10000 >> what power of 10 is it?
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
If you have problems understanding logarithms, always remember one thing: LOGARITHMS are EXPONENTS
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
In your problem, I also see a logarithm with base 3. I will call it b: \[\log_{3} 27=b\]So b is that logarithm, base 3 of 27. This means, because logarithms are exponents, \[3^b=27\]Now, 27, doesn't it sound familiar? Yes! It is a power of 3! In fact, it is 3³:\[3^b=3^3\]so b = 3. The right hand side of the problem doubles that number, so we have 6 there. Can you see now, why the left hand side is 6 as well?
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
Yea i guess so how do we answer this
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
Begin with the left hand side, replace log(100) and log(10000) with the numbers we've got. These will add up to 6. Right hand side is 2*3=6 also. Now you have shown that they are equal...
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
so 6 is the answeR?
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
If you reread the question, you'll see that "6" ids not the answer. You have to show that the left hand side and right hand side are equal. Although they seem very different, both sides give you 6 if you calculate them. Therefore they are equal. That is what you had to prove.
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
oh so how to i prove that with the equation right? i have no idea how to do this at all i know one side equals 6
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
how do we get 6 for the left hand side?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\(\log(100)\) measn \(\log_{10}(100)\) and since \(100=10^2\) we know \(\log(100)=2\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
last job is to solve \(\log(10000)\) i.e. solve \(10^y=10000\) for \(y\)
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
3 would be the y?
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 ?
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
What makes you think it is 3?
 one year ago

algebra2sucks Group TitleBest ResponseYou've already chosen the best response.0
because it has to equal to six idk i'm confused
 one year ago
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