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 one year ago
AP Calculus AB 2003 #2
http://www.collegeboard.com/prod_downloads/ap/students/calculus/calculus_ab_frq_03.pdf
I don't understand how to do part c).
 one year ago
AP Calculus AB 2003 #2 http://www.collegeboard.com/prod_downloads/ap/students/calculus/calculus_ab_frq_03.pdf I don't understand how to do part c).

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bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2total distance is integral of velocity but u gotta take into consideration which way it's going

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1I looked at the sample respoinses and they did like absolute value of v(t). But I don't understand why. http://apcentral.collegeboard.com/apc/public/repository/ap03_calculusab_q2_27980.pdf

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2so you found where it changes direction right?

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2the thing is...dw:1357322365854:dw

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2if u take just the integral, the area on the bottom gets subtracted

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2but that's for displacement. So if u want to get the distance you need to add that area instead of subtracting it.. So you have to integrate from start till when it changed direction, then from when it changed direction till when it changed direction again, etc.. and finally take the absolute value of all integrals and add them up

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2dw:1357322510296:dw see if u start at pt A, displacement, which is the regular integral, is 0, but distance traveled, is 5

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1i thought to find the distance u have to take integral of the velocity.

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2yes you do.. integral of velocity is indeed the area under the velocity curve, which is the displacement

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2so in order to get the DISTANCE.. you want to add all the areas that end up below y axis, instead of subtracting them

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2if you were looking for DISPLACEMENT, you would just take the integral of that function from 0 to 3. But, since you're looking for DISTANCE, take the integral of that function from 0 to a, where a is the time at which particle changed direction.

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2okay listen, where did the particle change direction?

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1yeah those were the solutions but only rad(2pi) works

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2no it was just t = 2.507

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1yeah that's rad(2pi)

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2so integrate that function from 0 to 2.507, then from 2.507 to 3

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2once you get the results, say Int from 0 to 2.507 = A, and Int from 2.507 to 3 = B; just add up the absolute values: A + B

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2that's all he's doing by integrating the absolute value of V over 0 < t < 3

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1how'd u integrate the function tho? like algebraically?

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2isn't that the calculator part?

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2i dont think u can integrate exponents inside trig functions yet.. lol

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1or do u just plug it into the graphing calculator? ohhh _ ok.

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2i mean i dont think there is a way that anyone has found how to do that

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1ohhh yeah i got the answer when i plugged it into the calculator

bahrom7893
 one year ago
Best ResponseYou've already chosen the best response.2You mean to tell me.... I WASTED MY TIME???!!!!!!

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1nooooooo...... like after you told me all that...

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1sorry..if anyone's still viewing this for part d) why did they add 1 to rad(2pi) ?
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