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Hint: apply the double angle formula

would i matter which side i start first ? :S

i am confused
why don't you just add \(\tan(2x)\) to both sides and get rid of it

because it's times

oh because it is times
doh

so wait...
2 tanx + 2a - 1 = tan2x - tan2x tan^2x
does that work?

if i bring tan2x to the right then bring 1 to the left side?

i think it is a bunch of algebra
i can try it with pencil and paper if you like

yes please? i want to understand how to do it.. i have a test coming up

im trying to do it myself as well

ok i screwed up already, let me try it again

lol i did too

this has nothing whatsoever to do with trig so fora as i can tell

ignoring the denominators, you ge t
\[2x-2x^3-2x+2a-2ax^2=1-x^2-2x^3\]
\[2a-2ax^2=1-x^2\]

and therefore \(a=\frac{1}{2}\)