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Question on Advanced function grade 12
Determine the value of "a" in the following equation :
2 tanx  tan2x + 2a = 1  tan2x ･ tan^2x
Hint: Double Angle Formula for Tangent is :
tan2x = 2tanx/1tan^2x
 one year ago
 one year ago
Question on Advanced function grade 12 Determine the value of "a" in the following equation : 2 tanx  tan2x + 2a = 1  tan2x ･ tan^2x Hint: Double Angle Formula for Tangent is : tan2x = 2tanx/1tan^2x
 one year ago
 one year ago

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bahrom7893Best ResponseYou've already chosen the best response.1
Hint: apply the double angle formula
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
would i matter which side i start first ? :S
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
i am confused why don't you just add \(\tan(2x)\) to both sides and get rid of it
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
oh because it is times doh
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
so wait... 2 tanx + 2a  1 = tan2x  tan2x tan^2x does that work?
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
if i bring tan2x to the right then bring 1 to the left side?
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
i think it is a bunch of algebra i can try it with pencil and paper if you like
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
yes please? i want to understand how to do it.. i have a test coming up
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
im trying to do it myself as well
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
ok i screwed up already, let me try it again
 one year ago

RadEnBest ResponseYou've already chosen the best response.0
from : tan2x = 2tanx/(1tan^2 x) 2tanx = tan2x(1tan^2 x) 2tanx = tan2x  tan2x tan^2 x now, apply it to left side
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
this has nothing whatsoever to do with trig so fora as i can tell
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
if we replace \(\tan(x)\) by \(x\) you get \[2x\frac{2x}{1x^2}+2a=1\frac{2x^3}{1x^2}\] now we add up on the left and right get \[\frac{2x(1x^2)2x+2a(1x^2)}{1x^2}=\frac{1x^22x^3}{1x^2}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
ignoring the denominators, you ge t \[2x2x^32x+2a2ax^2=1x^22x^3\] \[2a2ax^2=1x^2\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
and therefore \(a=\frac{1}{2}\)
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
wth! LOL that's the right answer... omg i was so off.... replacing tan(x) with "x" helped. thank you!
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
yeah that is a good trick to remember when you have a ton of annoying algebra to do it is good for all kinds of trig identities because almost all of the work is algebra, and you get too bogged down writing \(\sin(x)\) and \(\tan(x)\) when \(a\) or \(b\) would do
 one year ago
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