A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

hereweg0
 one year ago
Best ResponseYou've already chosen the best response.0it belongs in the math section

hereweg0
 one year ago
Best ResponseYou've already chosen the best response.0but okay. 3x  9y = 3 lets get x alone. 3x=3+9y

kasim17
 one year ago
Best ResponseYou've already chosen the best response.11)Elimination by coefficient method 3x  9y = 3 .....( i ) 6x  3y =  24 ...( ii ) Multiplying ( i ) by 2,we get 6x  18y = 6 .... ( iii ) Subtracting ( ii ) from ( iii ),we get 6x  18y = 6 6x  3y =  24 () (+) (+)   15y = 30 y =  2 Substituting y =  2 in ( ii ),we get 6x  3( 2) =  24 6x + 6 =  24 6x =  30 x =  5 x =  5 and y =  2 is the solution of given simultaneous equations. 2)Substitution method 3x  9y = 3 Dividing throughout by 3,we get x  3y = 1 x = 1 + 3y ..... ( i ) 6x  3y =  24 .....( ii ) Substituting ( i ) in ( ii ),we get 6(1 + 3y)  3y =  24 6 + 18y  3y =  24 15y =  30 y =  2 Substituting y =  2 in ( i ),we get x = 1 + 3y x = 1 + 3( 2) x = 1  6 x =  5 x =  5 and y =  2 is the solution of given simultaneous equations. According to me both the methods are efficient and easy. It varies from individual to individual to decide which method is efficient. So my opinion to you is that learn both the methods and practice hard and try to master them. !!!HOPE I HELPED!!!!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.