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hereweg0
 2 years ago
Best ResponseYou've already chosen the best response.0it belongs in the math section

hereweg0
 2 years ago
Best ResponseYou've already chosen the best response.0but okay. 3x  9y = 3 lets get x alone. 3x=3+9y

kasim17
 2 years ago
Best ResponseYou've already chosen the best response.11)Elimination by coefficient method 3x  9y = 3 .....( i ) 6x  3y =  24 ...( ii ) Multiplying ( i ) by 2,we get 6x  18y = 6 .... ( iii ) Subtracting ( ii ) from ( iii ),we get 6x  18y = 6 6x  3y =  24 () (+) (+)   15y = 30 y =  2 Substituting y =  2 in ( ii ),we get 6x  3( 2) =  24 6x + 6 =  24 6x =  30 x =  5 x =  5 and y =  2 is the solution of given simultaneous equations. 2)Substitution method 3x  9y = 3 Dividing throughout by 3,we get x  3y = 1 x = 1 + 3y ..... ( i ) 6x  3y =  24 .....( ii ) Substituting ( i ) in ( ii ),we get 6(1 + 3y)  3y =  24 6 + 18y  3y =  24 15y =  30 y =  2 Substituting y =  2 in ( i ),we get x = 1 + 3y x = 1 + 3( 2) x = 1  6 x =  5 x =  5 and y =  2 is the solution of given simultaneous equations. According to me both the methods are efficient and easy. It varies from individual to individual to decide which method is efficient. So my opinion to you is that learn both the methods and practice hard and try to master them. !!!HOPE I HELPED!!!!
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