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Using elimination, substitution solve c and b
C. y = 1\2x  6
2x + 6y = 19
B. 7x  3y = 20
5x + 3y = 16
 one year ago
 one year ago
Using elimination, substitution solve c and b C. y = 1\2x  6 2x + 6y = 19 B. 7x  3y = 20 5x + 3y = 16
 one year ago
 one year ago

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hereweg0Best ResponseYou've already chosen the best response.0
okay solve the second one for y
 one year ago

MrDoeBest ResponseYou've already chosen the best response.2
so for elimination, i suggest multiplying the first equation by negative 4 to get rid of x, than solve for y. for the substitution part, any one will work just fine, just isolate one variable
 one year ago

InspyR4DBest ResponseYou've already chosen the best response.1
7x  3y = 20 5x + 3y = 16 To eliminate you add together the top and bottom equation so you get 12x = 36 x= 3 Then you can work out y 5x3 +3y = 16 15+3y = 16 3y= 1 y= 1/3
 one year ago

MrDoeBest ResponseYou've already chosen the best response.2
watch it though inspy, i think that was a .5x
 one year ago

InspyR4DBest ResponseYou've already chosen the best response.1
The first one is wrong. I forgot to multiply the 6 by 6
 one year ago

MrDoeBest ResponseYou've already chosen the best response.2
y=.5x6 and 2x+6y=19 so multiply the first eq by 4 to get: 4y=2x24 = 4y2x=24 now take that and add the two to get: 10y=5 so y =1/2 then just solve for x using the known yvalue for the substitution: remember from your first eq that y=.5x6, so just sub that into the second eq: 2x+6(.5x6)=19 and solve
 one year ago

InspyR4DBest ResponseYou've already chosen the best response.1
y = 1\2x  6 2x + 6y = 19 6y = 3x36 6y= 192x 3x36=192x 5x= 55 x= 11 y= 0.5 Thanks Mr Doe
 one year ago

xBabyGirlxBest ResponseYou've already chosen the best response.0
i get it thanks you guys
 one year ago
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