Using elimination, substitution solve c and b
C. y = 1\2x - 6
2x + 6y = 19
B. 7x - 3y = 20
5x + 3y = 16
Stacey Warren - Expert brainly.com
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okay solve the second one for y
so for elimination, i suggest multiplying the first equation by negative 4 to get rid of x, than solve for y.
for the substitution part, any one will work just fine, just isolate one variable
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i'm so lost
inspy has it
i'm get that
7x - 3y = 20
5x + 3y = 16
To eliminate you add together the top and bottom equation so you get
12x = 36
Then you can work out y
5x3 +3y = 16
15+3y = 16
watch it though inspy, i think that was a .5x
The first one is wrong. I forgot to multiply the -6 by 6
y=.5x-6 and 2x+6y=19 so multiply the first eq by 4 to get:
4y=2x-24 = 4y-2x=-24 now take that and add the two to get:
10y=5 so y =1/2 then just solve for x using the known y-value
for the substitution:
remember from your first eq that y=.5x-6, so just sub that into the second eq: 2x+6(.5x-6)=19 and solve