## xBabyGirlx 2 years ago Using elimination, substitution solve c and b C. y = 1\2x - 6 2x + 6y = 19 B. 7x - 3y = 20 5x + 3y = 16

1. xBabyGirlx

@hereweg0

2. hereweg0

okay solve the second one for y

3. MrDoe

so for elimination, i suggest multiplying the first equation by negative 4 to get rid of x, than solve for y. for the substitution part, any one will work just fine, just isolate one variable

4. xBabyGirlx

i'm so lost

5. MrDoe

inspy has it

6. xBabyGirlx

i'm get that

7. InspyR4D

7x - 3y = 20 5x + 3y = 16 To eliminate you add together the top and bottom equation so you get 12x = 36 x= 3 Then you can work out y 5x3 +3y = 16 15+3y = 16 3y= 1 y= 1/3

8. MrDoe

watch it though inspy, i think that was a .5x

9. InspyR4D

The first one is wrong. I forgot to multiply the -6 by 6

10. MrDoe

y=.5x-6 and 2x+6y=19 so multiply the first eq by 4 to get: 4y=2x-24 = 4y-2x=-24 now take that and add the two to get: 10y=5 so y =1/2 then just solve for x using the known y-value for the substitution: remember from your first eq that y=.5x-6, so just sub that into the second eq: 2x+6(.5x-6)=19 and solve

11. InspyR4D

y = 1\2x - 6 2x + 6y = 19 6y = 3x-36 6y= 19-2x 3x-36=19-2x 5x= 55 x= 11 y= -0.5 Thanks Mr Doe

12. MrDoe