At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Make a drawing. Put the point (-5,40) in its proper position and then ask yourself: what is the shortest posible way to get from there to the x-axis?
In strict mathematical terms (and offered here this way so as to show the concept most clearly and completely) is to find the perpendicular distance from point (-5, -4) to the line y = 0. Therefore, you would take as the measure of that slope, the negative reciprocal of the slope of line y = 0, and that is an "undefined" slope, so we are talking about a vertical line or a vertical distance. The problem becomes much, much easier at this point because we don't have to come up with the equation of a line now. We can just find the distance from (-5, -4) and (-5, 0), and that distance is merely |-4| or 4.
@tcarroll010 ,Well That was ma answer (thats ma sis's question) However her question has the last solution which is the distance will be 10 ! Maybe we should use her lesson concept which is using da law : D= Root(x2-x1)+(y2_y1) ..
Where "y = 0" comes from is that that is the equation for the x-axis. You are essentially asking how to find the distance from a point to a line, so that is always a perpendicular distance. You can then generalize that concept to find the distance of any point to any line.
I thought I didn't give you a "hintless" answer ;) Also there is no need to use any kind of "law". It's just counting the boxes. (-5, -4) means you are 4 units below the x-axis, so that is the answer. It would be rather embarrassing to "calculate" it with the distance formula IMO.
In general, you would use the distance formula for the distance o a point to a line. But here, the x-coordinates will be the same, so the distance is just the "y- difference". For this specific problem. That is your quickest and legitimate approach. No need to over-complicate. I mentioned the the method in the first post as the general method. here, just take the "y difference".
I know ,But da final answer should be 10 .!
You could always use the disatance formula. You would find that: d = [(-5 - -5)^2 + (-4 - 0)^2]^(1/2) and that will come down to: (4^2)^(1/2) = 4 That's the hard way, but that will always work. Here, we can just take the difference of the "y- values"
It's like saying: 2+2=4, but it should be 10.
Alright ,Maybe Da final answer is mis-printed ..
K Ty Guys :P
and since the point on the x-axis that you are measring to is (-5, 0), all you are really doing is measuring the distance from -4 to 0. Which is merely 4.
thx for the recognition and good luck in all of your studies!