anonymous
  • anonymous
The Distance between the point (-5,-4) and the X-axis is ...... Length unit ~~~~~~~~ Guys I need an Urgent Help xD ..
Mathematics
katieb
  • katieb
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ZeHanz
  • ZeHanz
Make a drawing. Put the point (-5,40) in its proper position and then ask yourself: what is the shortest posible way to get from there to the x-axis?
anonymous
  • anonymous
@ZeHanz : :D that answer was the shortest and Hintless answer ?! I think i'am not able to measure it I should use da law ...
anonymous
  • anonymous
In strict mathematical terms (and offered here this way so as to show the concept most clearly and completely) is to find the perpendicular distance from point (-5, -4) to the line y = 0. Therefore, you would take as the measure of that slope, the negative reciprocal of the slope of line y = 0, and that is an "undefined" slope, so we are talking about a vertical line or a vertical distance. The problem becomes much, much easier at this point because we don't have to come up with the equation of a line now. We can just find the distance from (-5, -4) and (-5, 0), and that distance is merely |-4| or 4.

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anonymous
  • anonymous
@tcarroll010 ,Well That was ma answer (thats ma sis's question) However her question has the last solution which is the distance will be 10 ! Maybe we should use her lesson concept which is using da law : D= Root(x2-x1)+(y2_y1) ..
anonymous
  • anonymous
Where "y = 0" comes from is that that is the equation for the x-axis. You are essentially asking how to find the distance from a point to a line, so that is always a perpendicular distance. You can then generalize that concept to find the distance of any point to any line.
ZeHanz
  • ZeHanz
I thought I didn't give you a "hintless" answer ;) Also there is no need to use any kind of "law". It's just counting the boxes. (-5, -4) means you are 4 units below the x-axis, so that is the answer. It would be rather embarrassing to "calculate" it with the distance formula IMO.
anonymous
  • anonymous
In general, you would use the distance formula for the distance o a point to a line. But here, the x-coordinates will be the same, so the distance is just the "y- difference". For this specific problem. That is your quickest and legitimate approach. No need to over-complicate. I mentioned the the method in the first post as the general method. here, just take the "y difference".
anonymous
  • anonymous
I know ,But da final answer should be 10 .!
ZeHanz
  • ZeHanz
Why?
anonymous
  • anonymous
You could always use the disatance formula. You would find that: d = [(-5 - -5)^2 + (-4 - 0)^2]^(1/2) and that will come down to: (4^2)^(1/2) = 4 That's the hard way, but that will always work. Here, we can just take the difference of the "y- values"
ZeHanz
  • ZeHanz
It's like saying: 2+2=4, but it should be 10.
anonymous
  • anonymous
Alright ,Maybe Da final answer is mis-printed ..
anonymous
  • anonymous
K Ty Guys :P
anonymous
  • anonymous
and since the point on the x-axis that you are measring to is (-5, 0), all you are really doing is measuring the distance from -4 to 0. Which is merely 4.
anonymous
  • anonymous
thx for the recognition and good luck in all of your studies!

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