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OK, here is a differentiation problem that is baffling me  y = {ln[ln(ln x)]}  What is y prime? I am guessing the chain rule is the key here, but I cannot figure out the solution.
 one year ago
 one year ago
OK, here is a differentiation problem that is baffling me  y = {ln[ln(ln x)]}  What is y prime? I am guessing the chain rule is the key here, but I cannot figure out the solution.
 one year ago
 one year ago

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marsssBest ResponseYou've already chosen the best response.0
[ln(ln x)] = z and ln x = t => z = ln t y = ln z y(prime) = z(prime)/z z(prime) = t(prime)/t t(prime) = 1/x y(prime) = 1/xtz y(prime) = 1/x*ln x*ln(ln x)
 one year ago
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