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jennychan12
 3 years ago
Am I doing something wrong? See below.
jennychan12
 3 years ago
Am I doing something wrong? See below.

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jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits (x \sqrt{x+2})dx\]

jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0u = x+2 > x = u2 so \[\int\limits (u2)u^{\frac{ 1 }{ 2 }} du\] \[\int\limits u^{\frac{ 3 }{ 2 }}  2u^{\frac{ 1 }{ 2 }}\] am i correct so far? if i am i can do the rest

jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0oops. forgot the du on the last part

jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0If it is it'd be \[F(u) = \frac{ 2 }{ 5 } u^{\frac{ 5 }{ 2 }} \frac{ 4 }{ 3 }u^{\frac{ 3 }{ 2 }}\] and I'd just plug in the u's.

jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0oops forgot the +C I checked the answer and it'd partially correct. i got to the 2/5u..... i don't understand what they did after.

jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh ok lemme try that and see if i get it right.. :/

precal
 3 years ago
Best ResponseYou've already chosen the best response.0at the end they sub u back in

jennychan12
 3 years ago
Best ResponseYou've already chosen the best response.0_ that just makes more work oh well i got the answer, thanks.
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