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Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\int\limits (x \sqrt{x+2})dx\]
u = x+2 ---> x = u-2 so \[\int\limits (u-2)u^{\frac{ 1 }{ 2 }} du\] \[\int\limits u^{\frac{ 3 }{ 2 }} - 2u^{\frac{ 1 }{ 2 }}\] am i correct so far? if i am i can do the rest
oops. forgot the du on the last part

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Other answers:

If it is it'd be \[F(u) = \frac{ 2 }{ 5 } u^{\frac{ 5 }{ 2 }} -\frac{ 4 }{ 3 }u^{\frac{ 3 }{ 2 }}\] and I'd just plug in the u's.
true
oops forgot the +C I checked the answer and it'd partially correct. i got to the 2/5u..... i don't understand what they did after.
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they just factorise
ohhh ok lemme try that and see if i get it right.. :/
at the end they sub u back in
-_- that just makes more work oh well i got the answer, thanks.
cool

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