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\[\int\limits (x \sqrt{x+2})dx\]
u = x+2 ---> x = u-2 so \[\int\limits (u-2)u^{\frac{ 1 }{ 2 }} du\] \[\int\limits u^{\frac{ 3 }{ 2 }} - 2u^{\frac{ 1 }{ 2 }}\] am i correct so far? if i am i can do the rest
oops. forgot the du on the last part

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Other answers:

If it is it'd be \[F(u) = \frac{ 2 }{ 5 } u^{\frac{ 5 }{ 2 }} -\frac{ 4 }{ 3 }u^{\frac{ 3 }{ 2 }}\] and I'd just plug in the u's.
oops forgot the +C I checked the answer and it'd partially correct. i got to the 2/5u..... i don't understand what they did after.
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they just factorise
ohhh ok lemme try that and see if i get it right.. :/
at the end they sub u back in
-_- that just makes more work oh well i got the answer, thanks.

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