Here's the question you clicked on:
itsjustme_lol
x2 + 2x + 9 = 0
so, you have a quadratic equation \[x^2+2x+9=0\] where you want to solve for x ? Compare this quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
sorry, yes, i am here. but I already solved it on my own...thankyou though :D
good! welcome anyways ^_^