## gerryliyana Group Title W- Lambert function one year ago one year ago

1. abb0t

U ok? If it's a medical emergency, dial 9-1-1.

2. gerryliyana

I want to ask u about how to derive the 3rd Equation (On picture below), becomes the4th equation (on picture below) by using W-Lambert function ???

3. abb0t

I used to know this when I took an enzyme kinetics course and this derivation is long. About half a page - 1 page typed out.

4. abb0t

5. abb0t

It's a good paper :)

6. gerryliyana

i have been reading this paper, and I did not find what i want.., would u kindly help me?? do you still have a reference about this derivation (complete with W-Lambert function)

7. abb0t

I will look through my notes from my kinetics class. If I find it, I'll post it.

8. gerryliyana

ok thank u :)

9. gerryliyana

@UnkleRhaukus

10. UnkleRhaukus

hmm , i haven't heard of the W- Lambert function before

11. gerryliyana

do u have any idea @oldrin.bataku ??

12. oldrin.bataku

W(x) is defined such that W(x) e^W(x) = x

13. gerryliyana

yes.., i know.., i did read it on wikipedia. but I'm a little bit confused how to derive it (3rd equations) :)

14. gerryliyana

I'm looking for some easy derivation of the above, step by step., :)

15. oldrin.bataku

$$V_{max}t=([S_0]-[S](t))-K_M\ln\left(\frac{[S](t)}{[S_0]}\right)\\\ln\left(\frac{[S](t)}{[S_0]}\right)=\frac{[S_0]-[S](t)-V_{max}t}{K_M}\\\frac{[S](t)}{[S_0]}=\exp\left(\frac{[S_0]-[S](t)-V_{max}t}{K_M}\right)=\frac{e^\frac{{[S_0]-V_{max}t}}{K_M}}{\frac{e^{[S](t)}}{K_M}}$$ $$[S](t)e^{[S](t)}=\frac{S_0}{K_M}e^{\frac{[S_0]-V_{max}t}{K_m}}=\frac{S_0}{K_M}\exp\left(\frac{[S_0]-V_{max}t}{K_m}\right)$$ $$[S](t)=W\left(\frac{S_0}{K_M}\exp\left(\frac{[S_0]-V_{max}t}{K_m}\right)\right)$$

16. oldrin.bataku

It's just algebra :-p

17. abb0t

It is just algebra :) intense algebra.

18. gerryliyana

i thank all of u guys :)

19. gerryliyana

thank u so much @oldrin.bataku :)

20. oldrin.bataku

$$V_{max}t=([S_0]-[S](t))-K_M\ln\left(\frac{[S](t)}{[S_0]}\right)\\\ln\left(\frac{[S](t)}{[S_0]}\right)=\frac{[S_0]-[S](t)-V_{max}t}{K_M}\\\frac{[S](t)}{[S_0]}=\exp\left(\frac{[S_0]-[S](t)-V_{max}t}{K_M}\right)=\frac{e^\frac{{[S_0]-V_{max}t}}{K_M}}{e^\frac{[S](t)}{K_M}}$$$$\frac{[S](t)}{K_M}e^\frac{[S](t)}{K_M}=\frac{[S_0]}{K_M}e^{\frac{[S_0]-V_{max}t}{K_M}}=\frac{[S_0]}{K_M}\exp\left(\frac{[S_0]-V_{max}t}{K_M}\right)$$$$\frac{[S](t)}{K_M}=W\left[\frac{[S_0]}{K_M}\exp\left(\frac{[S_0]-V_{max}t}{K_M}\right)\right]$$$$[S](t)=K_MW\left[\frac{[S_0]}{K_M}\exp\left(\frac{[S_0]-V_{max}t}{K_M}\right)\right]$$Sorry, I made a few really dumb errors the first time! http://en.wikipedia.org/wiki/Michaelis%E2%80%93Menten_kinetics#Determination_of_constants

21. gerryliyana

ok.., no problem, thank u @oldrin.bataku ;)