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∫eˣ cot²(eˣ+1) dx. So far, I’ve put u = eˣ + 1 and du = eˣdx and substituted them in, so now I have ∫cot²u du. I’m not sure what to do next, since I can’t figure out the antiderivative for this!
 one year ago
 one year ago
∫eˣ cot²(eˣ+1) dx. So far, I’ve put u = eˣ + 1 and du = eˣdx and substituted them in, so now I have ∫cot²u du. I’m not sure what to do next, since I can’t figure out the antiderivative for this!
 one year ago
 one year ago

This Question is Closed

abb0tBest ResponseYou've already chosen the best response.1
\[\cot^2(u) = \csc^2(u)1\] Both of which are easily integrable.
 one year ago

ctmusicgirl7Best ResponseYou've already chosen the best response.0
so then i have ∫ (csc²u – 1) du?
 one year ago

ctmusicgirl7Best ResponseYou've already chosen the best response.0
the antiderivative of csc^2 u 1 = cot u  u?
 one year ago

ctmusicgirl7Best ResponseYou've already chosen the best response.0
thank you! is there some kind of thing on here where i give you points or something for helpuing me :D
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
Remember to plug u back in to the final answer and add the constant.
 one year ago

oldrin.batakuBest ResponseYou've already chosen the best response.0
@ctmusicgirl7 click "Best Response"
 one year ago
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