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ctmusicgirl7
 3 years ago
∫eˣ cot²(eˣ+1) dx. So far, I’ve put u = eˣ + 1 and du = eˣdx and substituted them in, so now I have ∫cot²u du. I’m not sure what to do next, since I can’t figure out the antiderivative for this!
ctmusicgirl7
 3 years ago
∫eˣ cot²(eˣ+1) dx. So far, I’ve put u = eˣ + 1 and du = eˣdx and substituted them in, so now I have ∫cot²u du. I’m not sure what to do next, since I can’t figure out the antiderivative for this!

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abb0t
 3 years ago
Best ResponseYou've already chosen the best response.1\[\cot^2(u) = \csc^2(u)1\] Both of which are easily integrable.

ctmusicgirl7
 3 years ago
Best ResponseYou've already chosen the best response.0so then i have ∫ (csc²u – 1) du?

ctmusicgirl7
 3 years ago
Best ResponseYou've already chosen the best response.0the antiderivative of csc^2 u 1 = cot u  u?

ctmusicgirl7
 3 years ago
Best ResponseYou've already chosen the best response.0thank you! is there some kind of thing on here where i give you points or something for helpuing me :D

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.1Remember to plug u back in to the final answer and add the constant.

oldrin.bataku
 3 years ago
Best ResponseYou've already chosen the best response.0@ctmusicgirl7 click "Best Response"
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