A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
∫eˣ cot²(eˣ+1) dx. So far, I’ve put u = eˣ + 1 and du = eˣdx and substituted them in, so now I have ∫cot²u du. I’m not sure what to do next, since I can’t figure out the antiderivative for this!
anonymous
 3 years ago
∫eˣ cot²(eˣ+1) dx. So far, I’ve put u = eˣ + 1 and du = eˣdx and substituted them in, so now I have ∫cot²u du. I’m not sure what to do next, since I can’t figure out the antiderivative for this!

This Question is Closed

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.1\[\cot^2(u) = \csc^2(u)1\] Both of which are easily integrable.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then i have ∫ (csc²u – 1) du?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the antiderivative of csc^2 u 1 = cot u  u?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you! is there some kind of thing on here where i give you points or something for helpuing me :D

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.1Remember to plug u back in to the final answer and add the constant.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ctmusicgirl7 click "Best Response"
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.