Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
An equation of a circle is x^2 + y^2 + 10x – 6y + 18 = 0. Show all your work in determining the center and radius of this circle. In complete sentences, explain the procedure used.
 one year ago
 one year ago
An equation of a circle is x^2 + y^2 + 10x – 6y + 18 = 0. Show all your work in determining the center and radius of this circle. In complete sentences, explain the procedure used.
 one year ago
 one year ago

This Question is Closed

abb0tBest ResponseYou've already chosen the best response.1
The form of the circle is: \[(xh)+(yk) = r^2 \] where (h,k) is the center of the circle, and r is the radius. What you want to do is rearrange it to get it in that form. Use algebra to group (not combine) like terms. Then complete the square
 one year ago

mitchelsewbaranBest ResponseYou've already chosen the best response.0
what is h and k in this equation?
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
Well, that's up to you to figure out. First, group like terms: \[(x^2+10x)+(y^26y)+18 = 0\] Then, proceed to complete the square for x and y to get it in the form I stated earlier. Does that make more sense?
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
To complete the square: \[ax^2+bx + e\] you add to both sides (including product side): \[(\frac{ b }{ 2 })^2 \]
 one year ago

mitchelsewbaranBest ResponseYou've already chosen the best response.0
i know how to complete the square
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.