A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
An equation of a circle is x^2 + y^2 + 10x – 6y + 18 = 0. Show all your work in determining the center and radius of this circle. In complete sentences, explain the procedure used.
 2 years ago
An equation of a circle is x^2 + y^2 + 10x – 6y + 18 = 0. Show all your work in determining the center and radius of this circle. In complete sentences, explain the procedure used.

This Question is Closed

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.1The form of the circle is: \[(xh)+(yk) = r^2 \] where (h,k) is the center of the circle, and r is the radius. What you want to do is rearrange it to get it in that form. Use algebra to group (not combine) like terms. Then complete the square

mitchelsewbaran
 2 years ago
Best ResponseYou've already chosen the best response.0what is h and k in this equation?

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.1Well, that's up to you to figure out. First, group like terms: \[(x^2+10x)+(y^26y)+18 = 0\] Then, proceed to complete the square for x and y to get it in the form I stated earlier. Does that make more sense?

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.1To complete the square: \[ax^2+bx + e\] you add to both sides (including product side): \[(\frac{ b }{ 2 })^2 \]

mitchelsewbaran
 2 years ago
Best ResponseYou've already chosen the best response.0i know how to complete the square
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.