An equation of a circle is x^2 + y^2 + 10x – 6y + 18 = 0. Show all your work in determining the center and radius of this circle. In complete sentences, explain the procedure used.

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An equation of a circle is x^2 + y^2 + 10x – 6y + 18 = 0. Show all your work in determining the center and radius of this circle. In complete sentences, explain the procedure used.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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The form of the circle is: \[(x-h)+(y-k) = r^2 \] where (h,k) is the center of the circle, and r is the radius. What you want to do is rearrange it to get it in that form. Use algebra to group (not combine) like terms. Then complete the square
what is h and k in this equation?
Well, that's up to you to figure out. First, group like terms: \[(x^2+10x)+(y^2-6y)+18 = 0\] Then, proceed to complete the square for x and y to get it in the form I stated earlier. Does that make more sense?

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Other answers:

To complete the square: \[ax^2+bx + e\] you add to both sides (including product side): \[(\frac{ b }{ 2 })^2 \]
i know how to complete the square
gotcha.

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