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Let C be the circle with centre(0,0) ,radius=3units..The eq.of locus of midpoints of the chords of the circle that substend an angle 2pi/3 at centre=?
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experimentX
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your question is misleading ... try to elaborate a bit.
DLS
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what ismissing?
IsTim
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Maybe a diagram?
IsTim
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I'm actually not certain.
DLS
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not given
experimentX
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oh!! that would be crystal clear.
Are the midpoints of chords subtending 2pi/3 at center?
hartnn
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|dw:1357461802327:dw|
something like this ?
shubhamsrg
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|dw:1357461806933:dw|
distance between (h,k) and center = 3 co60
DLS
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@experimentX yes
DLS
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how did we get pi/3?
shubhamsrg
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|dw:1357461957504:dw|
so that'd be half of it,ofcorse..
you can relate this from the fact that both right triangles are congruent..
DLS
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explain that r=Rcos30 thing :S
experimentX
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|dw:1357461938365:dw|
shubhamsrg
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@@experimentX you misunderstood.
it says the locus of mid points of all those chords, which subtend angle 2pi/3 at center
the chord subtends angle 2pi/3 at the center..
experimentX
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|dw:1357462092588:dw|
DLS
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|dw:1357462129634:dw|
DLS
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R=3 given
DLS
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|dw:1357462305603:dw|
DLS
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didnt get why r=Rcos30
experimentX
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|dw:1357462348001:dw|
DLS
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then?
experimentX
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your equation will be a circle with center at 0,0 ... just find the radius using trigonometry.
sauravshakya
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|dw:1357471539024:dw|
sauravshakya
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As @experimentX said use trigonometry to find OM
sauravshakya
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Then find the equation of the circle with center O and radius=OM
DLS
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Last thing,what will be the radius of the circle(i.e locus) of midpoint of chords?OM?why?
experimentX
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|dw:1357497953902:dw|
DLS
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R=3cos 60
yeah ive got that
DLS
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Is R^2=27/4?
DLS
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and what is the radius of the locus :/