A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
a wire of resistance 12 ohms is bent in the form of circle.what is the effective resistance between a and b?
anonymous
 3 years ago
a wire of resistance 12 ohms is bent in the form of circle.what is the effective resistance between a and b?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1357465781135:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you please tell me, how to solve this problem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ghazi @evergirl @mathslover help..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@pdvpa please explain

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I think 3 ohms is right. Each semicircle between A and B is 6 ohms (half the 12 ohms of the full wire). Two 6 ohm wires in parallel is equivalent to one 3 ohm wire. No need to use the formula, the area across each wire is added when they are side by side so the resistance is halved to 3 ohms.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how could you consider it as two sepearte pieces when they are a single entity of a wire made of a material having 12 ohm resistance..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hi mathavraj, Yes you are right, the wire is a single piece that forms a circle. Your drawing shows A opposite B. There are two paths for the electricity or current to flow from A to B. As each path appears to be the same length (A opposite B on the circle) each path will have a resistance of 6 ohms because it is half the length of the full wire. Two 6 ohms paths in parallel (sharing the current flow) is equivalent to one 3 ohm path between A and B.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im sorry @oceanok i still dont get it..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1362654142306:dw Hi, Good morning mathavraj, hope you are well. We are clearly thinking about the problem in different ways. I will try to understand how you are thinking. The current does not flow in a circle around the full length of the wire. Forget for the moment that the circle was made from a single length of wire and just approach the problem as it is now. Imagine a stream with water flowing down from a high point at A to a low point at B. The stream divides in two. Each side is a semicircle (the shape is not that important) both of equal length. The sides meet again at B to form a single stream again. It is the same with the electrical circuit. The current enters at A divides into two equal amounts (both flowing towards B). The flow of current is eased because each semi circle is only half the length of the original wire, so each side is 6 ohms. Also each side is now sharing the overall flow from A to B so the total resistance is halved again to 3 ohms. This circle froms part of the circuit with perhaps a battery connected between A and B. The current is not flowing in a circle around the 12 ohm wire but flowing from A to B in two sides of the circle. The original wire is joined at the open ends to form a circle, it is not open ended.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@oceanoak thanks man..nw i get it...:)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.