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a wire of resistance 12 ohms is bent in the form of circle.what is the effective resistance between a and b?
 one year ago
 one year ago
a wire of resistance 12 ohms is bent in the form of circle.what is the effective resistance between a and b?
 one year ago
 one year ago

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mathavrajBest ResponseYou've already chosen the best response.4
dw:1357465781135:dw
 one year ago

Kathi26Best ResponseYou've already chosen the best response.0
Can you please tell me, how to solve this problem?
 one year ago

mathavrajBest ResponseYou've already chosen the best response.4
@ghazi @evergirl @mathslover help..
 one year ago

mathavrajBest ResponseYou've already chosen the best response.4
@pdvpa please explain
 one year ago

oceanoakBest ResponseYou've already chosen the best response.1
Yes, I think 3 ohms is right. Each semicircle between A and B is 6 ohms (half the 12 ohms of the full wire). Two 6 ohm wires in parallel is equivalent to one 3 ohm wire. No need to use the formula, the area across each wire is added when they are side by side so the resistance is halved to 3 ohms.
 one year ago

mathavrajBest ResponseYou've already chosen the best response.4
how could you consider it as two sepearte pieces when they are a single entity of a wire made of a material having 12 ohm resistance..
 one year ago

oceanoakBest ResponseYou've already chosen the best response.1
Hi mathavraj, Yes you are right, the wire is a single piece that forms a circle. Your drawing shows A opposite B. There are two paths for the electricity or current to flow from A to B. As each path appears to be the same length (A opposite B on the circle) each path will have a resistance of 6 ohms because it is half the length of the full wire. Two 6 ohms paths in parallel (sharing the current flow) is equivalent to one 3 ohm path between A and B.
 one year ago

mathavrajBest ResponseYou've already chosen the best response.4
im sorry @oceanok i still dont get it..
 one year ago

oceanoakBest ResponseYou've already chosen the best response.1
dw:1362654142306:dw Hi, Good morning mathavraj, hope you are well. We are clearly thinking about the problem in different ways. I will try to understand how you are thinking. The current does not flow in a circle around the full length of the wire. Forget for the moment that the circle was made from a single length of wire and just approach the problem as it is now. Imagine a stream with water flowing down from a high point at A to a low point at B. The stream divides in two. Each side is a semicircle (the shape is not that important) both of equal length. The sides meet again at B to form a single stream again. It is the same with the electrical circuit. The current enters at A divides into two equal amounts (both flowing towards B). The flow of current is eased because each semi circle is only half the length of the original wire, so each side is 6 ohms. Also each side is now sharing the overall flow from A to B so the total resistance is halved again to 3 ohms. This circle froms part of the circuit with perhaps a battery connected between A and B. The current is not flowing in a circle around the 12 ohm wire but flowing from A to B in two sides of the circle. The original wire is joined at the open ends to form a circle, it is not open ended.
 one year ago

mathavrajBest ResponseYou've already chosen the best response.4
@oceanoak thanks man..nw i get it...:)
 one year ago
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