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jiteshmeghwal9
 3 years ago
If \(\LARGE{x^2=\frac{1}{x^2}+1}\), then \(\LARGE{x^2+\frac{1}{x^2}=?}\)
jiteshmeghwal9
 3 years ago
If \(\LARGE{x^2=\frac{1}{x^2}+1}\), then \(\LARGE{x^2+\frac{1}{x^2}=?}\)

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jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1@hartnn @ParthKohli @ajprincess plz help :)

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\dfrac{1}{x^2} = x^2  1 \ \ \ \ \]So,\[x^2 + x^2  1 = 2x^2 1\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Should it be a number value?

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Huge{\color{red}{Ans.\sqrt{5}}}\]

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3x^4 = x^2 + 1 x^4  x^2  1 = 0 put y = x^2

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0That's a quartic equation in \(x\). So multiply through \(x^2\).\[x^4 = x^2 + 1\]

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1from where do u gt x^4?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0I had typed a long explanation, but Yahoo! spilled the beans =P

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3Solve the given Equation @jiteshmeghwal9 x^2 = 1 + 1/x^2

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\(x^2 = 1 + \dfrac{1}{x^2}\) is what you have. Multiply \(x^2\) to both sides.

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1Oops sorry i misread it

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1AArgh.... I'm going to be crazy :(

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry dudes but i'm nt getting the right thing :(

rahul91
 3 years ago
Best ResponseYou've already chosen the best response.0x^4x^21=0 put x^2=t t^2t1=0 solve it

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1using quadratic formula ?

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1\[{1 \pm \sqrt{1+4}\over2}={1 \pm \sqrt{5}\over2}\]

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1No.. i'm nt getting answer

rahul91
 3 years ago
Best ResponseYou've already chosen the best response.0substitute for x^2 in the expression needed

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3Hm..Hm...After Solving i got sqrt5

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1can anybody give me steps to the solution, i'm getting confused :((((

rahul91
 3 years ago
Best ResponseYou've already chosen the best response.0hey substitute x^2= (1sqrt(5))/2 in the expression u get the answer sqrt(5)

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3@jiteshmeghwal9 ..Can u Check...ur Solution

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3x^2 + 1 / x^2 = (x^4 + 1) / x^2

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\[x^4 x^2  1 = 0 \]We can let \(t = x^2\).\[t^2  t  1 = 0 \iff \boxed{t = \dfrac{1\pm \sqrt 5}{2}}{}\]

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3x^4=x^2+1 (x^2+2) / x^2 = 1 + 2/x^2

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1\[x^2=1/x^2+1\\x^4=1+x^2\\x^4x^21=0\]by quadratic formula,\[x^2=\frac{1\pm \sqrt{5}}{2}\]disregard \(\displaystyle x^2= \frac{1\sqrt{5}}{2}\) since this is not a real number

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1well \(\sqrt{5}=\pm\sqrt{5}\) but in my book it is only given \(\sqrt{5}\) as answer :)

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3Lol....Then...Go By My method

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.31 + 2/x^2 1 + 4 / (1 + sqrt5) (5 + sqrt5)/ (1 + sqrt5) rationalize... u will get (4 sqrt 5)/4 = sqrt5

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1A little doubt here, just last doubt

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1(x^2+2) / x^2 = 1 + 2/x^2 how did u gt this ?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1\[x^2=\frac{1+\sqrt 5}{2}\\\frac{1}{x^2}=\frac{2}{1+\sqrt 5}\cdot\frac{1\sqrt 5}{1\sqrt 5}=\frac{1}{2}+\frac{\sqrt 5}{2}\\x^2+\frac{1}{x^2}=(1/2+\sqrt 5/2)+(1/2+\sqrt 5/2)=\sqrt {5}\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\dfrac{x^2 + 2}{x^2} = \dfrac{x^2}{x^2} + \dfrac{2}{x^2}\cdots\]

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1I m just gt confused just like my bro @maheshmeghwal9 :(

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.3Oh...i just Did to make calculation easy....if u dont get it...Go My The method used by sirm

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1Well...now i gt it, thanx all of u a lot :) Mainly @Yahoo! thanx buddy ;)
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