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jiteshmeghwal9
Group Title
If \(\LARGE{x^2=\frac{1}{x^2}+1}\), then \(\LARGE{x^2+\frac{1}{x^2}=?}\)
 one year ago
 one year ago
jiteshmeghwal9 Group Title
If \(\LARGE{x^2=\frac{1}{x^2}+1}\), then \(\LARGE{x^2+\frac{1}{x^2}=?}\)
 one year ago
 one year ago

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jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
@hartnn @ParthKohli @ajprincess plz help :)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[\dfrac{1}{x^2} = x^2  1 \ \ \ \ \]So,\[x^2 + x^2  1 = 2x^2 1\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Should it be a number value?
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
\[\Huge{\color{red}{Ans.\sqrt{5}}}\]
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
x^4 = x^2 + 1 x^4  x^2  1 = 0 put y = x^2
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
wait..
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
That's a quartic equation in \(x\). So multiply through \(x^2\).\[x^4 = x^2 + 1\]
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
from where do u gt x^4?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I had typed a long explanation, but Yahoo! spilled the beans =P
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Solve the given Equation @jiteshmeghwal9 x^2 = 1 + 1/x^2
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\(x^2 = 1 + \dfrac{1}{x^2}\) is what you have. Multiply \(x^2\) to both sides.
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
x^4=x^2+1
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
That...
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
Oops sorry i misread it
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
AArgh.... I'm going to be crazy :(
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
Sorry dudes but i'm nt getting the right thing :(
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
Need help
 one year ago

rahul91 Group TitleBest ResponseYou've already chosen the best response.0
x^4x^21=0 put x^2=t t^2t1=0 solve it
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
using quadratic formula ?
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
\[{1 \pm \sqrt{1+4}\over2}={1 \pm \sqrt{5}\over2}\]
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
No.. i'm nt getting answer
 one year ago

rahul91 Group TitleBest ResponseYou've already chosen the best response.0
substitute for x^2 in the expression needed
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Hm..Hm...After Solving i got sqrt5
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
can anybody give me steps to the solution, i'm getting confused :((((
 one year ago

rahul91 Group TitleBest ResponseYou've already chosen the best response.0
hey substitute x^2= (1sqrt(5))/2 in the expression u get the answer sqrt(5)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
@jiteshmeghwal9 ..Can u Check...ur Solution
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Is it sqrt5 or sqrt5
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
x^2 + 1 / x^2 = (x^4 + 1) / x^2
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[x^4 x^2  1 = 0 \]We can let \(t = x^2\).\[t^2  t  1 = 0 \iff \boxed{t = \dfrac{1\pm \sqrt 5}{2}}{}\]
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
x^4=x^2+1 (x^2+2) / x^2 = 1 + 2/x^2
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.1
\[x^2=1/x^2+1\\x^4=1+x^2\\x^4x^21=0\]by quadratic formula,\[x^2=\frac{1\pm \sqrt{5}}{2}\]disregard \(\displaystyle x^2= \frac{1\sqrt{5}}{2}\) since this is not a real number
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
nw put the value of x^2
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
well \(\sqrt{5}=\pm\sqrt{5}\) but in my book it is only given \(\sqrt{5}\) as answer :)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Lol....Then...Go By My method
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
ohh! k
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
1 + 2/x^2 1 + 4 / (1 + sqrt5) (5 + sqrt5)/ (1 + sqrt5) rationalize... u will get (4 sqrt 5)/4 = sqrt5
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Nw u Got it...:)
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
A little doubt here, just last doubt
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Wat?@jiteshmeghwal9
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
(x^2+2) / x^2 = 1 + 2/x^2 how did u gt this ?
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.1
\[x^2=\frac{1+\sqrt 5}{2}\\\frac{1}{x^2}=\frac{2}{1+\sqrt 5}\cdot\frac{1\sqrt 5}{1\sqrt 5}=\frac{1}{2}+\frac{\sqrt 5}{2}\\x^2+\frac{1}{x^2}=(1/2+\sqrt 5/2)+(1/2+\sqrt 5/2)=\sqrt {5}\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[\dfrac{x^2 + 2}{x^2} = \dfrac{x^2}{x^2} + \dfrac{2}{x^2}\cdots\]
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
I m just gt confused just like my bro @maheshmeghwal9 :(
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Oh...i just Did to make calculation easy....if u dont get it...Go My The method used by sirm
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
Well...now i gt it, thanx all of u a lot :) Mainly @Yahoo! thanx buddy ;)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.3
Well..)) .welcome
 one year ago
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