Goten77
  • Goten77
simple order of operations question.... problem is that ive heard 2 stories question below
Mathematics
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SOLVED
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katieb
  • katieb
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Goten77
  • Goten77
\[6\div 2(2+1)=?\]
Goten77
  • Goten77
i know order of operations is par thesis 1st... so it becomes \[6\div 2(3)\] but then isnt it multiplication 1st then division? or arent they on the same level? or does that parenthesis around the 3 make any change?.... ive heard stories now
hba
  • hba
9

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hba
  • hba
We can follow, PEMDAS or BODMAS.
hartnn
  • hartnn
not again!
hba
  • hba
BODMAS means Bracket of division multiplication addition and subtraction.
Goten77
  • Goten77
so basically \[6\div 2(3) = 6\div 2 \times 3\]
Goten77
  • Goten77
and the parenthesis around 3 has no effect?
hba
  • hba
Not in this case.
Goten77
  • Goten77
well since what your saying is true * i believe* that means on a old question on here some1 told me a different story and i didnt feel like arguing .... but yes he obviously told them wrong but oh well.. just making sure
hartnn
  • hartnn
when you have only multiplications and division, the order of evaluation is from left to right. and a(b) is ecactly same as a*b.
Goten77
  • Goten77
thats what i thought @hartnn but this guy said it was multiplication then division..... and i knew it had to b wrong
hartnn
  • hartnn
multiplication and division have exactly equal priorities.

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