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Goten77

  • 2 years ago

simple order of operations question.... problem is that ive heard 2 stories question below

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  1. Goten77
    • 2 years ago
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    \[6\div 2(2+1)=?\]

  2. Goten77
    • 2 years ago
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    i know order of operations is par thesis 1st... so it becomes \[6\div 2(3)\] but then isnt it multiplication 1st then division? or arent they on the same level? or does that parenthesis around the 3 make any change?.... ive heard stories now

  3. hba
    • 2 years ago
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    9

  4. hba
    • 2 years ago
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    We can follow, PEMDAS or BODMAS.

  5. hartnn
    • 2 years ago
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    not again!

  6. hba
    • 2 years ago
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    BODMAS means Bracket of division multiplication addition and subtraction.

  7. Goten77
    • 2 years ago
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    so basically \[6\div 2(3) = 6\div 2 \times 3\]

  8. Goten77
    • 2 years ago
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    and the parenthesis around 3 has no effect?

  9. hba
    • 2 years ago
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    Not in this case.

  10. Goten77
    • 2 years ago
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    well since what your saying is true * i believe* that means on a old question on here some1 told me a different story and i didnt feel like arguing .... but yes he obviously told them wrong but oh well.. just making sure

  11. hartnn
    • 2 years ago
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    when you have only multiplications and division, the order of evaluation is from left to right. and a(b) is ecactly same as a*b.

  12. Goten77
    • 2 years ago
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    thats what i thought @hartnn but this guy said it was multiplication then division..... and i knew it had to b wrong

  13. hartnn
    • 2 years ago
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    multiplication and division have exactly equal priorities.

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