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simple order of operations question.... problem is that ive heard 2 stories question below

Mathematics
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\[6\div 2(2+1)=?\]
i know order of operations is par thesis 1st... so it becomes \[6\div 2(3)\] but then isnt it multiplication 1st then division? or arent they on the same level? or does that parenthesis around the 3 make any change?.... ive heard stories now
  • hba
9

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Other answers:

  • hba
We can follow, PEMDAS or BODMAS.
not again!
  • hba
BODMAS means Bracket of division multiplication addition and subtraction.
so basically \[6\div 2(3) = 6\div 2 \times 3\]
and the parenthesis around 3 has no effect?
  • hba
Not in this case.
well since what your saying is true * i believe* that means on a old question on here some1 told me a different story and i didnt feel like arguing .... but yes he obviously told them wrong but oh well.. just making sure
when you have only multiplications and division, the order of evaluation is from left to right. and a(b) is ecactly same as a*b.
thats what i thought @hartnn but this guy said it was multiplication then division..... and i knew it had to b wrong
multiplication and division have exactly equal priorities.

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