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Circle problem

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Please refer to the attachment.
1 Attachment
Intuitively, I think I is correct. But I don't know how to ensure the other two are correct or not..
  • DLS
3rd seems correct :P

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Other answers:

I think you are right about I. The sum of the angles is always 1080 degrees. II is also right, because of this: imagine O is at height h above line CD. If you draw a horizontal line through O, it intersect both AC and BD, lets say in A' and B'. Then it is easy to see that triangles AA'O and BB'O are congruent. This means AA'=BB'=a. SO AC = h-a and BD = h+a, total length is 2h, so constant. U can use this also to reason whether ACxBC is constant or not!
TYPO: 180 deg ;)
Why is ACxBD NOT constant? (so III is false).
  • DLS
oh:o not constant yeah
So, C and D are not fixed point, i.e. they'll change when the diameter rotates. AC // BD, so theta + phi must be 180 degrees (int. angles, AC//BD) The two triangles are congruent (ASA), so both sides have the same (magnitude of) change. And AC+BD would remain constant as 2h. And the last point: AC x BD = (h-a)(h+a) = h^2 - a^2, which is not a constant. So, it's the answer. Thanks everyone!!!
  • DLS
like i said :3

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