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RolyPoly

Circle problem

  • one year ago
  • one year ago

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  1. RolyPoly
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    Please refer to the attachment.

    • one year ago
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  2. RolyPoly
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    Intuitively, I think I is correct. But I don't know how to ensure the other two are correct or not..

    • one year ago
  3. DLS
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    3rd seems correct :P

    • one year ago
  4. ZeHanz
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    I think you are right about I. The sum of the angles is always 1080 degrees. II is also right, because of this: imagine O is at height h above line CD. If you draw a horizontal line through O, it intersect both AC and BD, lets say in A' and B'. Then it is easy to see that triangles AA'O and BB'O are congruent. This means AA'=BB'=a. SO AC = h-a and BD = h+a, total length is 2h, so constant. U can use this also to reason whether ACxBC is constant or not!

    • one year ago
  5. ZeHanz
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    TYPO: 180 deg ;)

    • one year ago
  6. ZeHanz
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    Why is ACxBD NOT constant? (so III is false).

    • one year ago
  7. DLS
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    oh:o not constant yeah

    • one year ago
  8. ZeHanz
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    (h+a)(h-a)=...

    • one year ago
  9. sirm3d
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    |dw:1357564433476:dw|

    • one year ago
  10. RolyPoly
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    So, C and D are not fixed point, i.e. they'll change when the diameter rotates. AC // BD, so theta + phi must be 180 degrees (int. angles, AC//BD) The two triangles are congruent (ASA), so both sides have the same (magnitude of) change. And AC+BD would remain constant as 2h. And the last point: AC x BD = (h-a)(h+a) = h^2 - a^2, which is not a constant. So, it's the answer. Thanks everyone!!!

    • one year ago
  11. sirm3d
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    yw.

    • one year ago
  12. ZeHanz
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    yw!

    • one year ago
  13. DLS
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    like i said :3

    • one year ago
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