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ksaimouli
Group Title
find intersection in terms of y of y^24x=4and 4xy=16
 one year ago
 one year ago
ksaimouli Group Title
find intersection in terms of y of y^24x=4and 4xy=16
 one year ago
 one year ago

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ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
\[y^24x=4 and 4xy=16\]
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Hint: y = 4x  16
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i did but i dont know whre i was wrong
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i know dude to solve for x and set it eual and then solve for x
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1357491125167:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1357491191134:dw
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Don't make it complicated bro
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1357491240591:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
solve for y am i right this is to find area between curve sooo i must to with respect y
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Actually, that's a good approach after all.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
but something is wrong in solving hmm i am not getting the answer
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
multiply both sides by 4
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
What did you get for the answer?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
.08 and 12.08
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
That's what you got for y values?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i gote it 5 and 4
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Okay, so what's the problem?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
arithmetic mistake lol
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
now i have to integrate thats it
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1357491558149:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
but not sure which one goes top and which goes bottom with respect to y
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Here's another way to do it to avoid confusion: \[\frac{y^2  4}{4}  \frac{16 + y}{4} = 0\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
ya i tried that worked well
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Bro, a is always the lowest value. b is always the highest value.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i mean the function not the points (curves)
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{ y^24 }{ 4 }\]
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Are you sure you're supposed to be using y values for a and b?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
or\[x=\frac{ 16+y }{ 4 }\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
ya i am damn sure
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
I remember these. They can be tricky. What you do is just turn your graph sideways. And it will be the same as like when you're working with xaxis.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
if \[\sqrt{y}\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1357491948129:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
alright thx
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Bro, I graphed it as \[\frac{16 + x}{4}\] and \[\frac{x^2  4}{4}\] You get the same area when integrating from a = 4 to b = 5 The only difference is you're using variable y instead of variable x
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
ya i noticed it thx
 one year ago
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