Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ksaimouli Group Title

find intersection in terms of y of y^2-4x=4and 4x-y=16

  • one year ago
  • one year ago

  • This Question is Closed
  1. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[y^2-4x=4 and 4x-y=16\]

    • one year ago
  2. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @ZeHanz

    • one year ago
  3. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Hint: y = 4x - 16

    • one year ago
  4. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i did but i dont know whre i was wrong

    • one year ago
  5. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i know dude to solve for x and set it eual and then solve for x

    • one year ago
  6. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1357491125167:dw|

    • one year ago
  7. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1357491191134:dw|

    • one year ago
  8. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Don't make it complicated bro

    • one year ago
  9. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1357491240591:dw|

    • one year ago
  10. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    solve for y am i right this is to find area between curve sooo i must to with respect y

    • one year ago
  11. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Actually, that's a good approach after all.

    • one year ago
  12. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    but something is wrong in solving hmm i am not getting the answer

    • one year ago
  13. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    multiply both sides by 4

    • one year ago
  14. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    What did you get for the answer?

    • one year ago
  15. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    .08 and -12.08

    • one year ago
  16. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    That's what you got for y values?

    • one year ago
  17. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    nope

    • one year ago
  18. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i gote it 5 and -4

    • one year ago
  19. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Okay, so what's the problem?

    • one year ago
  20. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    arithmetic mistake lol

    • one year ago
  21. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    now i have to integrate thats it

    • one year ago
  22. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1357491558149:dw|

    • one year ago
  23. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    but not sure which one goes top and which goes bottom with respect to y

    • one year ago
  24. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Here's another way to do it to avoid confusion: \[\frac{y^2 - 4}{4} - \frac{16 + y}{4} = 0\]

    • one year ago
  25. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ya i tried that worked well

    • one year ago
  26. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Bro, a is always the lowest value. b is always the highest value.

    • one year ago
  27. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i mean the function not the points (curves)

    • one year ago
  28. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[x=\frac{ y^2-4 }{ 4 }\]

    • one year ago
  29. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Are you sure you're supposed to be using y values for a and b?

    • one year ago
  30. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    or\[x=\frac{ 16+y }{ 4 }\]

    • one year ago
  31. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ya i am damn sure

    • one year ago
  32. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    I remember these. They can be tricky. What you do is just turn your graph sideways. And it will be the same as like when you're working with x-axis.

    • one year ago
  33. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    if \[\sqrt{y}\]

    • one year ago
  34. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1357491948129:dw|

    • one year ago
  35. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ?

    • one year ago
  36. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    alright thx

    • one year ago
  37. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Bro, I graphed it as \[\frac{16 + x}{4}\] and \[\frac{x^2 - 4}{4}\] You get the same area when integrating from a = -4 to b = -5 The only difference is you're using variable y instead of variable x

    • one year ago
  38. Hero Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    @ksaimouli

    • one year ago
  39. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ya i noticed it thx

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.