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ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1\[y^24x=4 and 4xy=16\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1i did but i dont know whre i was wrong

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1i know dude to solve for x and set it eual and then solve for x

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1357491125167:dw

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1357491191134:dw

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Don't make it complicated bro

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1357491240591:dw

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1solve for y am i right this is to find area between curve sooo i must to with respect y

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Actually, that's a good approach after all.

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1but something is wrong in solving hmm i am not getting the answer

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1multiply both sides by 4

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2What did you get for the answer?

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2That's what you got for y values?

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Okay, so what's the problem?

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1arithmetic mistake lol

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1now i have to integrate thats it

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1357491558149:dw

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1but not sure which one goes top and which goes bottom with respect to y

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Here's another way to do it to avoid confusion: \[\frac{y^2  4}{4}  \frac{16 + y}{4} = 0\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1ya i tried that worked well

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Bro, a is always the lowest value. b is always the highest value.

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1i mean the function not the points (curves)

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{ y^24 }{ 4 }\]

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Are you sure you're supposed to be using y values for a and b?

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1or\[x=\frac{ 16+y }{ 4 }\]

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2I remember these. They can be tricky. What you do is just turn your graph sideways. And it will be the same as like when you're working with xaxis.

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1357491948129:dw

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2Bro, I graphed it as \[\frac{16 + x}{4}\] and \[\frac{x^2  4}{4}\] You get the same area when integrating from a = 4 to b = 5 The only difference is you're using variable y instead of variable x
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