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wesleyho

  • 3 years ago

Integrate by using the substitution u = 2x -1 for ∫ sqrt 2x+1 dx from 0 to 2

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  1. ParthKohli
    • 3 years ago
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    \[du = 2 dx\]

  2. ParthKohli
    • 3 years ago
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    \[dx = 0.5du\]

  3. hartnn
    • 3 years ago
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    do you mean u=2x+1 ? or sqrt{2x-1} ?

  4. ParthKohli
    • 3 years ago
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    \[0.5 \int_{0}^{2} \sqrt{u} du\]The question is wrong, and whatever the question is, this is true

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