## wesleyho Group Title Integrate by using the substitution u = 2x -1 for ∫ sqrt 2x+1 dx from 0 to 2 one year ago one year ago

1. ParthKohli Group Title

$du = 2 dx$

2. ParthKohli Group Title

$dx = 0.5du$

3. hartnn Group Title

do you mean u=2x+1 ? or sqrt{2x-1} ?

4. ParthKohli Group Title

$0.5 \int_{0}^{2} \sqrt{u} du$The question is wrong, and whatever the question is, this is true