wesleyho
Integrate by using the substitution u = 2x 1 for ∫ sqrt 2x+1 dx from 0 to 2



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ParthKohli
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\[du = 2 dx\]

ParthKohli
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\[dx = 0.5du\]

hartnn
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do you mean u=2x+1 ? or sqrt{2x1} ?

ParthKohli
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\[0.5 \int_{0}^{2} \sqrt{u} du\]The question is wrong, and whatever the question is, this is true