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\[\lim_{n \rightarrow \infty}(\frac{ 1 }{ 1*3 }+\frac{ 1 }{ 3*5 }+......\frac{ 1 }{ (2n1)(2n+1) })\]
 one year ago
 one year ago
Yahoo! Group Title
\[\lim_{n \rightarrow \infty}(\frac{ 1 }{ 1*3 }+\frac{ 1 }{ 3*5 }+......\frac{ 1 }{ (2n1)(2n+1) })\]
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
2=31 so, 1/1*3 = 1/2(2/1*3) = 1/2((31)/3*1) = 1/2[11/3] do this for every term. should i do it in latex, or you got it ?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Latex...Plzz
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1}{1 \times 3}=\frac{1}{2} \times \frac{2}{1 \times 3}=\frac{1}{2} \times[\frac{31}{1 \times 3}]=\frac{1}{2} \times[\frac{1}{1 }\frac{1}{ 3}]\] do this for every term.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
2nd term = 1/3 1/5 notice 1/3 will get cancelled, and if you go on, all the terms excepts 1st and last will get cancelled.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Would u Call This Partial Fraction Decomposition?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes. i would.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
it would be n /(2n+1) ryt? @hartnn
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
then limit=... ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
use the telescopic's principle, it can be 1/2 (1  1/(2n+1)) 1/2 (2n/(2n+1)) just look the cofficient of n, they are same) :)
 one year ago
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