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\[\lim_{x \rightarrow \frac{ \Pi }{ 2 }} (cosx)^{cosx}\]
 one year ago
 one year ago
Yahoo! Group Title
\[\lim_{x \rightarrow \frac{ \Pi }{ 2 }} (cosx)^{cosx}\]
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
use log. take log on both sides.
 one year ago

ASAAD123 Group TitleBest ResponseYou've already chosen the best response.0
ln y=cosx ln(cosx)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
cos x * log cos x (cosx / cos x) * sinx + log cos x *  sinx
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what is this ?? (cosx / cos x) * sinx + log cos x *  sinx
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
you can use LH only if you have 0/0 or infinity/infinity form
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Huh..i Just Forgot that..)
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
this is same as x^x x>0 try this x^x = e^(x log(x))
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, log cos x/ sec x now try LH
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because cos =1/sec that should work, i think....
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
that certainly works ... but this seems interesting ... using substitution. let cos(x) = u, then we have u > 0 , u^u ... i think you might have done before.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
something like sin /(sec cos tan) = cos log L = 0 L=1
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
you got 2 methods :) understood both ??
 one year ago
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