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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1use log. take log on both sides.

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0cos x * log cos x (cosx / cos x) * sinx + log cos x *  sinx

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1what is this ?? (cosx / cos x) * sinx + log cos x *  sinx

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1you can use LH only if you have 0/0 or infinity/infinity form

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0Huh..i Just Forgot that..)

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.2this is same as x^x x>0 try this x^x = e^(x log(x))

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so, log cos x/ sec x now try LH

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1because cos =1/sec that should work, i think....

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.2that certainly works ... but this seems interesting ... using substitution. let cos(x) = u, then we have u > 0 , u^u ... i think you might have done before.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1something like sin /(sec cos tan) = cos log L = 0 L=1

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1you got 2 methods :) understood both ??
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