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\[\lim_{x \rightarrow \frac{ \Pi }{ 2 }} (cosx)^{cosx}\]

Mathematics
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use log. take log on both sides.
ln y=cosx ln(cosx)
cos x * log cos x (cosx / cos x) * -sinx + log cos x * - sinx

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Other answers:

what is this ?? (cosx / cos x) * -sinx + log cos x * - sinx
you can use LH only if you have 0/0 or infinity/infinity form
Huh..i Just Forgot that..)
this is same as x^x x->0 try this x^x = e^(x log(x))
so, log cos x/ sec x now try LH
because cos =1/sec that should work, i think....
that certainly works ... but this seems interesting ... using substitution. let cos(x) = u, then we have u -> 0 , u^u ... i think you might have done before.
something like -sin /(sec cos tan) = -cos log L = 0 L=1
you got 2 methods :) understood both ??
Yup..)

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