anonymous
  • anonymous
Please help! Gerry is 4 years younger than Tom.If Tom is t years old, how old is Gerry? I know how to write the expression, but I don't know how to solve. Please help! Thanks!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
hmmm tom is t years old and gerry is 4 years YOUNGER!
anonymous
  • anonymous
yeah t-4.Ok now how you solve it?
anonymous
  • anonymous
thats all.. thats the answer! :P

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anonymous
  • anonymous
hm. okay i guess. How about this one: 150 people went to see "Ode to Algebra" performed in the school auditorium. If the number of children that attend the performance was, c, how many adults attend?
anonymous
  • anonymous
you tell.. 150 people went to see it children were C.. so how many left?
anonymous
  • anonymous
i don't know, thats why I'm asking I'm a bit confused. Can you please explain?
anonymous
  • anonymous
total people 150.. out of them 'c' number of them were kids.. so how many left??
anonymous
  • anonymous
I'm sorry I'm lost. Its confusing me, wouldn't it be 150=a+c ?? I'm sorry I don't really understand.
anonymous
  • anonymous
lets start simple if i said.. out of 10 people 4 were children.. how many are adults?
anonymous
  • anonymous
6
anonymous
  • anonymous
so that was 10 - 4 similarly out of 150.. c number of them are children.. hence the answer would be???
anonymous
  • anonymous
OH. 150?
anonymous
  • anonymous
:O c is a variable.. c could be 1 or 2 or 150... so the answer is 150 - c
anonymous
  • anonymous
I feel stupid. But WHY would it be 1 , 2 , or 150?
anonymous
  • anonymous
thats algebra.. its a variable.. a variable could be any number!!! so in general.. it would be 150 - c
anonymous
  • anonymous
Oh. okay. But since its saying to find the amt of adults, then wouldn't it be 150-c=a ?
anonymous
  • anonymous
ok ok. yes.. 'a' is a variable that you are assigning to adults :)..
anonymous
  • anonymous
Ohh ok! Thank you so much!
anonymous
  • anonymous
no probs ;-)
anonymous
  • anonymous
hey can you help me again??

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