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What's the vertex of y=x^2+6x+8?(

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x-coordinate of vertex when y=ax^2+bx+c = -b/2a
Start by completing the square first.
Once you have the x-coordinate you can easily solve for y-coordinate by plugging in

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Other answers:

the answer is {-3,-1} have a nice day=D
HINT: Remember that the vertex form is: \[y = a(x-h)^2+k\]
aw thanks=D Im really good with problems that don't involve words lol
giving away the answer doesn't help the person learn, @Helly :P
How do you figure out if its the maximum or minimum?
Is the curve going up or down? Look at the sign of "a"
You could take a few derivatives.

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