Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Sheridan16

  • 3 years ago

What's the vertex of y=x^2+6x+8?(

  • This Question is Open
  1. BluFoot
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    x-coordinate of vertex when y=ax^2+bx+c = -b/2a

  2. abb0t
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Start by completing the square first.

  3. BluFoot
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Once you have the x-coordinate you can easily solve for y-coordinate by plugging in

  4. Helly
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the answer is {-3,-1} have a nice day=D

  5. abb0t
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    HINT: Remember that the vertex form is: \[y = a(x-h)^2+k\]

  6. Helly
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    aw thanks=D Im really good with problems that don't involve words lol

  7. abb0t
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    giving away the answer doesn't help the person learn, @Helly :P

  8. Helly
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    SORRY=(

  9. Sheridan16
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    How do you figure out if its the maximum or minimum?

  10. BluFoot
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Is the curve going up or down? Look at the sign of "a"

  11. abb0t
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You could take a few derivatives.

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy