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binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0did you write this down correctly

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0are you sure the last one shouldn't be \[1  2 \cos^{2}(x) \] instead of 1  2 cos 2x

VeroZarate
 one year ago
Best ResponseYou've already chosen the best response.0yes that is what i meant sorry it didnt square it

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0Ok try starting by rewriting tan x as sin x / cos x and cot x as cos x / sin x

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0\[(\sin x)(\frac{ \sin x }{ \cos x } * \cos x  \frac{ \cos x }{ \sin x } * \cos x) = 1  2 \cos^{2} x\]

VeroZarate
 one year ago
Best ResponseYou've already chosen the best response.0ok so cos^2x/sinx ?

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0it would become \[(\sin x)(\sin x  \frac{ \cos^{2} x }{ \sin x }) = 1  2 \cos^{2} x\] then \[\sin^{2} x  \cos^{2} x = 1  2 \cos^{2} x\]

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0last step would just be add 2 cos^2(x) to both sides

VeroZarate
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand where the 2cos^2x came from

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0there is already a 2 cos^2 x in the problem. the last step is to add 2 cos^2 x to both sides this way the right side becomes: 1 and the left side becomes: sin^2 x + cos^2 x

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0and we have the identity \[\sin^{2} x + \cos^{2} x = 1\]

VeroZarate
 one year ago
Best ResponseYou've already chosen the best response.0oh ok i understand! thanks! do you think you can help me out with another one?

binarymimic
 one year ago
Best ResponseYou've already chosen the best response.0sure but they recommend you close this question and start another one

VeroZarate
 one year ago
Best ResponseYou've already chosen the best response.0ok so ill open another
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