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What are the real or imaginary solutions of the polynomial equation? x3 – 8 =0
 one year ago
 one year ago
What are the real or imaginary solutions of the polynomial equation? x3 – 8 =0
 one year ago
 one year ago

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StiwanBest ResponseYou've already chosen the best response.0
well, what you've got here is \[x^3 = 8\] so x equals 2. The solution is unique, so there is no other solution
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
That's not true, there are two complex solutions as well...
 one year ago

T0mmyBest ResponseYou've already chosen the best response.0
Sure the question is right?
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Perfectly valid question. Use the difference of cubes formula provided above by @Hero and then use the quadratic formula on the second part to determine the two complex roots.
 one year ago
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