Here's the question you clicked on:
andee
What are the real or imaginary solutions of the polynomial equation? x3 – 8 =0
well, what you've got here is \[x^3 = 8\] so x equals 2. The solution is unique, so there is no other solution
That's not true, there are two complex solutions as well...
Sure the question is right?
Perfectly valid question. Use the difference of cubes formula provided above by @Hero and then use the quadratic formula on the second part to determine the two complex roots.